Answer : The de Broglie wavelength will be 
Solution :
The formula used for de Broglie wavelength is:
..........(1)
where,
= wavelength = ?
h = Planck's constant = 
m = mass = 1.2 g = 0.0012 kg
Conversion used : 1 kg = 1000 g
v = velocity = 150 m/s
Now put all the given values in equation 1, we get:
Therefore, the de Broglie wavelength will be
One way they are different is that they show elevation
Ka is the equilibrium constant for the ionization for a reaction. It is calculated as follows
ka is equal to (H3o ions)(A-) divided by (HA)
2.00x106i s equal to 0.153x0.153 divided by ( HA)
(2.00x106)HA is equal to 0.023409
HA concentration is therefore equal to 0.023409/2.00x106 which is 1.104x10^-4moles/litre
Francium is the heaviest of the alkali metals, with an atomic mass of 223 grams.
Answer:
m-CPBA followed by base catalysed hydrolysis
Explanation:
The scheme of this reaction is shown in the image attached.
We can see here that the acetophenone reacts with metachloroperoxybenzoic acid (m-CPBA) as shown in the image to yield phenyl acetate.
Phenyl acetate is now hydrolysed by a base as shown to yield the acetate ion and phenol.
