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PilotLPTM [1.2K]
3 years ago
10

If I wanted to generate a maximum emf of 20 V, what angular velocity (radians/sec, aka Hz) would be required given a circular co

il of wire with diameter 40 cm and 500 coils? The coil rotates through a magnet field of magnitude 9e-3 T which is directed such that the angle between the area vector and the magnet field vector varies from 0 to 2 π radians.
Physics
1 answer:
sergij07 [2.7K]3 years ago
6 0

Answer:

Angular velocity, \omega=35.36\ rad/s

Explanation:

It is given that,

Maximum emf generated in the coil, \epsilon=20\ V

Diameter of the coil, d = 40 cm

Radius of the coil, r = 20 cm = 0.2 m

Number of turns in the coil, N = 500

Magnetic field in the coil, B=9\times 10^{-3}\ T

The angle between the area vector and the magnet field vector varies from 0 to 2 π radians. The formula for the maximum emf generated in the coil is given by :

\epsilon=NBA\omega

\omega=\dfrac{\epsilon}{NBA}

\omega=\dfrac{20\ V}{500\times 9\times 10^{-3}\ T\times \pi (0.2\ m)^2}

\omega=35.36\ rad/s

So, the angular velocity of the circular coil is 35.36 rad/s. Hence, this is the required solution.

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