Answer:
a) 0.64 b) 2.17m/s^2 c) 8.668joules
Explanation:
The block was on the ramp, the ramp was inclined at 20degree. A force of 5N was acting horizontal to the but not parallel to the ramp,
Frictional force = horizontal component of the weight of the block along the ramp + the applied force since the block was just about move
Frictional force = mgsin20o + 5N = 6.71+5N = 11.71
The force of normal = the vertical component of the weight of the block =mgcos20o = 18.44
Coefficient of static friction = 11.71/18.44= 0.64
Remember that g = acceleration due to gravity (9.81m/s^2) and m = mass (2kg)
b) coefficient of kinetic friction = frictional force/ normal force
Fr = 0.4* mgcos 20o = 7.375N
F due to motion = ma = total force - frictional force
Ma = 11.71 - 7.375 = 4.335
a= 4.335/2(mass of the block) = 2.17m/s^2
C) work done = net force *distance = 4.335*2= 8.67Joules
Answer: A 2.00-kilogram object weighs 19.6 newtons on Earth.
Explanation:
Answer:
distance = 6.1022 x10^16[m]
Explanation:
To solve this problem we must use the formula of the average speed which relates distance to time, so we have
v = distance / time
where:
v = velocity = 3 x 10^8 [m/s]
distance = x [meters]
time = 6.45 [light years]
Now we have to convert from light-years to seconds in order to get the distance in meters.
Now using the formula:
distance = v * time
distance = (3*10^8)*203407200
distance = 6.1022 x10^16[m]
Answer:
A. 65 degrees
Explanation:
The formula to calculate the range of a projectile is:
where
u is the initial speed of the projectile
g is the acceleration of gravity
is the angle of projection of the projectile
We want to find the angle such that it has the same range of a projectile fired at , therefore:
It follows that
And there are two angles that satisfies this condition:
and
In fact, with the second choice,
Answer:
a = 200 m/s²
Explanation:
Given,
The initial speed of rocket-powered sled, u = 0
The final speed of rocket-powered sled, v = 440 m/s
Time taken to reach final speed, t = 2.20 s
The acceleration of the body is given by the change in velocity by time
a = (v - u) / t
= (440 - 0) / 2.20
= 200 m/s²
Therefore, the acceleration of the rocket-powered sled, a = 200 m/s²