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Alik [6]
3 years ago
12

A person fires a 38 gram bullet straight up into the air. It rises, then falls straight back down, striking the ground with a sp

eed of 345 m/s. The bullet embeds itself into the ground a distance of 8.9 cm before coming to a stop. What force does the ground exert on the bullet? Express your answer in newtons.
Physics
1 answer:
Y_Kistochka [10]3 years ago
4 0

Answer:

Force exerted = 25.41 kN

Explanation:

We have equation of motion

      v² = u²+2as

u = 345 m/s, s = 8.9 cm = 0.089 m, v = 0 m/s

     0² = 345²+2 x a x 0.089

       a = -668679.78 m/s²

Force exerted = Mass x Acceleration

Mass of bullet = 38 g = 0.038 kg

Acceleration = 668679.78 m/s²

Force exerted = 25409.83 N = 25.41 kN

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Atomic nuclei are made of protons and neutrons. This fact by itself shows thatthere must be some other type of force in addition
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5 0
3 years ago
a ball is thrown inclined in to the air with a initial velocity of u. if it reaches the maximum height in 6 seconds , find the r
olga55 [171]

Answer:

11:1

Explanation:

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Substituting:

y = 6g t − ½g t²

The displacement between t=0 and t=1 is:

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3 years ago
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The correct answers are as follows:
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2)sand and gravel

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7 0
3 years ago
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