The amount of steering wheel movement needed to turn will ____________ the faster you go.

Physics

2 answers:

Naddika [18.5K]2 years ago

4 0

Answer:

The answer to your question is Decrease

Svetach [21]2 years ago

3 0

Answer:

<h2>The amount of steering wheel movement needed to turn will <u><em>decrease</em></u> the faster you go.</h2>

Explanation:

A steering wheel, a driving wheel or a hand wheel allow us to control the vehicle, it's part of the steering. So the faster the vehicle goes, less movement of the wheel is needed, because the movement of the vehicle makes easier to handle the wheel. Also, when the vehicle is almost not moving or moving slowly, we have to put more effort to move the wheel.

In addition, this want of the reasons why when we are driving too fast, we must put attention on our wheel, because a simple and short movement can get us out of the road.

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A mass of 240 grams oscillates on a horizontal frictionless surface at a frequency of 2.5 Hz and with amplitude of 4.5 cm.

mr_godi [17]

Answer:

(a) The spring constant is 59.23 N/m

(b) The total energy involved in the motion is 0.06 J

Explanation:

Given;

mass, m = 240 g = 0.24 kg

frequency, f = 2.5 Hz

amplitude of the oscillation, A = 4.5 cm = 0.045 m

The angular speed is calculated as;

ω = 2πf

ω = 2 x π x 2.5

ω = 15.71 rad/s

(a) The spring constant is calculated as;

$\omega = \sqrt{\frac{k}{m} } \\\\\omega ^2 = \frac{k}{m} \\\\k = m\omega ^2\\\\where;\\\\k \ is \ the \ spring \ constant\\\\k = (0.24) \times (15.71)^2\\\\k = 59.23 \ N/m$

(b) The total energy involved in the motion;

E = ¹/₂kA²

E = (0.5) x (59.23) x (0.045)²

E = 0.06 J

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aivan3 [116]

Answer:

Explanation:

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A 2 kg picture frame sits on a shelf at a height of 0.5 m. how much gravitational potential energy is added to the picture frame

AysviL [449]

The change in gravitational potential energy is A) 15.68 J

Explanation:

The gravitational potential energy of an object is the energy possessed by the object due to its position in the gravitational field.

The change in gravitational potential energy of an object is given by the equation:

$\Delta U = mg\Delta h$