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zzz [600]
3 years ago
5

The amount of steering wheel movement needed to turn will ____________ the faster you go.

Physics
2 answers:
Naddika [18.5K]3 years ago
4 0

Answer:

The answer to your question is Decrease

Svetach [21]3 years ago
3 0

Answer:

<h2>The amount of steering wheel movement needed to turn will <u><em>decrease</em></u> the faster you go.</h2>

Explanation:

A steering wheel, a driving wheel or a hand wheel allow us to control the vehicle, it's part of the steering. So the faster the vehicle goes, less movement of the wheel is needed, because the movement of the vehicle makes easier to handle the wheel. Also, when the vehicle is almost not moving or moving slowly, we have to put more effort to move the wheel.

In addition, this want of the reasons why when we are driving too fast, we must put attention on our wheel, because a simple and short movement can get us out of the road.

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As a substance melts, heat energy is used to break the connections between molecules, and temperature __________ until all melti
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Temperature stays the same
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Which list of elements contains only metals?
fredd [130]
C. those are all metals.
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4 years ago
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How would you find the total energy stored in the
likoan [24]

Answer:

The energy of the capacitors connected in parallel is 0.27 J

Given:

C = 2.0\micro F = 2.0\times 10^{- 6} F

C' = 4.0\micro F = 4.0\times 10^{- 6} F

Potential difference, V = 300 V

Solution:

Now, we know that the equivalent capacitance of the two parallel connected capacitors is given by:

C_{eq} = C + C' = 2.0 + 4.0 = 6.0\micro F = 6.0\times 10^{- 6} F

The energy of the capacitor, E is given by;

E = \frac{1}{2}C_{eq}V^{2}

E = \frac{1}{2}\times 6.0\times 10^{- 6}\times 300^{2} = 0.27 J

6 0
3 years ago
Wil-E-Coyote drops a bowling ball off a cliff to try to catch the Roadrunner. The cliff is
PtichkaEL [24]

Answer:

t = 5.19 s

Explanation:

We have,

Height of the cliff is 132 m

It is required to find the time taken by the ball to fall to the ground. Let t is the time taken. So, using equation of kinematics as :

y=ut+\dfrac{1}{2}gt^2\\\\\text{since}\ u=0\\\\y=\dfrac{1}{2}gt^2\\\\t=\sqrt{\dfrac{2y}{g}}\\\\t=\sqrt{\dfrac{2\times 132}{9.8}}\\\\t=5.19\ s

So, it will take 5.19 seconds to fall to the ground.

8 0
3 years ago
A 47-kg packing crate is pulled with constant speed across a rough floor with a rope that is at an angle of 37 degrees above the
levacccp [35]

Tension in the rope due to applied force will be given as

F = 142 N

angle of applied force with horizontal is 37 degree

displacement along the floor = 6.1 m

so here we can use the formula of work done

W = F d cos\theta

now we can plug in all values above

W = 142 * 6.1 * cos37

W = 691.8 J

So here work done to pull is given by 691.8 J


8 0
3 years ago
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