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Aleks [24]
3 years ago
13

What kind of energy does an unlit match have?

Physics
1 answer:
Rudiy273 years ago
6 0
It’s is none of the above answers.
It is d. Potential energy
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When you step inside a warm ski lodge on a cold day, you find your glasses fog. why does this occur?
marin [14]
Answer: Condensation of moisture in the air onto the glasses.

Explanation:
When you come from a cold environment into a warm ski lodge, the glasses are at a much lower temperature than that of the lodge.
Because the air in the room contains moisture (water vapor), it condenses on a surface whose temperature is lower than the dew point of the room. 
5 0
3 years ago
What gives an atom its charge?
s344n2d4d5 [400]
An atom<span> with a neutral </span>charge<span> is one where the number of electrons is equal to the </span>atomic<span> number

hope i helped</span>
5 0
3 years ago
Read 2 more answers
How do I solve this step by step? I’m really confused
LekaFEV [45]

Step-#1:

Ignore the wire on the right.

Find the strength and direction of the magnetic field at P,

caused by the wire on the left, 0.04m away, carrying 5.0A

of current upward.

Write it down.


Step #2:

Now, ignore the wire on the left.

Find the strength and direction of the magnetic field at P,

caused by the wire on the right, 0.04m away, carrying 8.0A

of current downward.

Write it down.


Step #3:

Take the two sets of magnitude and direction that you wrote down

and ADD them.


The total magnetic field at P is the SUM of (the field due to the left wire)

PLUS (the field due to the right wire).


So just calculate them separately, then addum up.

4 0
3 years ago
A basketball player of height 2.40 m is standing 2.60 m in front of a convex spherical mirror of radius of curvature 4.00 m. Det
IrinaVladis [17]

Answer:

The size of the image is 1.04 m.

Explanation:

Given that,

Height of object = 2.40 m

Distance of object = 2.60 m

Radius of curvature =4.00 m

Focal length f=\dfrac{R}{2}=\dfrac{4.00}{2}=2.00

We need to calculate the image distance

Using mirror formula

\dfrac{1}{f}=\dfrac{1}{v}+\dfrac{1}{u}

\dfrac{1}{v}=\dfrac{1}{2.00}+\dfrac{1}{2.60}

\dfrac{1}{v}= \dfrac{23}{26}

v=1.13\ cm

We need to calculate the height of the image

Using formula of magnification

m=\dfrac{h'}{h}=-\dfrac{v}{u}

Put the value into the formula

\dfrac{h'}{2.40}=-\dfrac{1.13}{-2.60}

h'=\dfrac{1.13}{2.60}\times2.40

h'=1.04\ m

Hence, The size of the image is 1.04 m

8 0
3 years ago
What is the change in electric potential energy when the dipole moment of a molecule changes its orientation with respect to e⃗
AleksandrR [38]

Electric potential energy of a dipole is given as

U = - P.E

U = - PE cos\theta

so change in the potential energy is given by

U_f - U_i = (-PEcos\theta_2)- (-PEcos\theta_1)

\Delta U = PE (cos\theta_1 - cos\theta_2)

here initially it was parallel to electric field while finally it is perpendicular to the electric field

so we have

\Delta U = PE(cos 0 - cos 90)

\Delta U = PE

so above is the change in potential energy of dipole

8 0
3 years ago
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