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4 years ago

Simplify the expression. w^5(w^2)^-4

Mathematics

1 answer:

Sergeeva-Olga [200]4 years ago

8 0

W⁵(w²)⁻⁴ = w⁵(w⁻⁸) = w⁵⁺⁽⁻⁸⁾ = w⁻³

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Rachel earned $85.25 for working 6 1 4 hours. How much does Rachel earn per hour?

GaryK [48]

Answer:

Rachel earns per hour is $ 13.64 .

Step-by-step explanation:

As given

Rachel earned $85.25 for working $6 \frac{1}{4}$ hours.

i.e

Rachel earned $85.25 for working $\frac{25}{4}$ hours.

Now calculate earning of Rachel for 1 hour .

$Rachel\ earning\ for\ one\ hour = \frac{Total\ earning}{Total\ time}$

$Rachel\ earning\ for\ one\ hour = \frac{85.25}{\frac{25}{4}}$

$Rachel\ earning\ for\ one\ hour = \frac{85.25\times 4}{25}$

$Rachel\ earning\ for\ one\ hour = \frac{341}{25}$

$Rachel\ earning\ for\ one\ hour = \$ 13.64$

Therefore Rachel earns per hour is $ 13.64 .

7 0

3 years ago

Read 2 more answers

-3x-9=-15 solve for x

qaws [65]

Answer:x=2

Step-by-step explanation:

-3x-9=-15

-3x=-6

x=2

7 0

3 years ago

Read 2 more answers

What are three equivalent ratios for 5/45

Burka [1]

$\frac{5}{45}=5:45\ and\ \frac{5}{45}=\frac{5:5}{45:5}=\frac{1}{9}\\\\\frac{5}{45}=\frac{1}{9}\to\boxed{1:9}\\\\\frac{5}{45}=\frac{1}{9}=\frac{1\cdot2}{9\cdot2}=\frac{2}{18}=\boxed{2:18}\\\\\frac{5}{45}=\frac{1}{9}=\frac{1\cdot3}{9\cdot3}=\frac{3}{27}=\boxed{3:27}\\\\\frac{5}{45}=\frac{1}{9}=\frac{1\cdot4}{9\cdot4}=\frac{4}{36}=\boxed{4:36}\\\vdots$

7 0

3 years ago

One batch of fruit punch contains 1/3 quart grape juice and 1/5 quart apple juice. Colby makes 11 batches of fruit punch. How mu

zhuklara [117]

Answer:

3.66666666667

Step-by-step explanation:

If you multiply the number of batches he makes and the amount of grape juice he needs for every quart, you get and answer of 3.66666666667.

1/3 * 11= 3.66666666667

If you need to round the answer it would be 3.67

8 0

3 years ago

PLEASE HELP I NEED THIS ASAP<br> Find the vertex of y=x^2-7x+4

Goshia [24]

Answer:

$\mathrm{Minimum}\space\left(\frac{7}{2},\:-\frac{33}{4}\right)$

Step-by-step explanation:

$y=x^2-7x+4\\\mathrm{The\:vertex\:of\:an\:up-down\:facing\:parabola\:of\:the\:form}\:y=ax^2+bx+c\:\mathrm{is}\:x_v=-\frac{b}{2a}\\\mathrm{The\:parabola\:params\:are:}\\a=1,\:b=-7,\:c=4\\x_v=-\frac{b}{2a}\\x_v=-\frac{\left(-7\right)}{2\cdot \:1}\\\mathrm{Simplify}\\x_v=\frac{7}{2}\\\mathrm{Plug\:in}\:\:x_v=\frac{7}{2}\:\mathrm{to\:find\:the}\:y_v\:\mathrm{value}\\y_v=\left(\frac{7}{2}\right)^2-7\cdot \frac{7}{2}+4\\$

$\mathrm{Simplify\:}\left(\frac{7}{2}\right)^2-7\cdot \frac{7}{2}+4:\quad -\frac{33}{4}\\y_v=-\frac{33}{4}\\Therefore\:the\:parabola\:vertex\:is\\\left(\frac{7}{2},\:-\frac{33}{4}\right)\\\mathrm{If}\:a0,\:\mathrm{then\:the\:vertex\:is\:a\:minimum\:value}\\a=1\\\mathrm{Minimum}\space\left(\frac{7}{2},\:-\frac{33}{4}\right)$

6 0

4 years ago