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3 years ago

9

Explain the connections between reactants, products, and limiting reactant.

1 answer:

sineoko [7]3 years ago

6 0

Reactants is a starting substance in a chemical reaction; (reactants appear on the left-hand side of a chemical equation).
Products is a substance produced in a chemical reaction; (products appear on the right-hand side of a chemical equation).
Limiting reactant is the reactant that has the smallest stoichiometric amount in a reactant mixture and consequently limits the amount of product in a chemical reaction.

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The alarm at a fire station rings and a 87.5-kg fireman, starting from rest, slides down a pole to the floor below (a distance o

blsea [12.9K]

Answer:

$F_f=840N$

Explanation:

From the question we are told that

Weight of fireman $W_f= 87.5kg$

Pole distance $D=4.10m$

Final speed is $V_f 1.75m/s$

Generally the equation for velocity is mathematically represented as

$v^2 = v_0^2 + 2 a d$

Therefore Acceleration a

$a'= v^2 / 2 d$

$a'= 0.21m/s^2$

Generally the equation for Frictional force $F_f$ is mathematically given as

$F_f=m*a$

$F_f=m*(g-0.21)$

$F_f=87.5*(9.81-0.21)$

Therefore

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6 0

3 years ago

How do you determine the wattage capacity needed by a power supply?

Lady bird [3.3K]

We could use the formula for the Power supply in order to find the wattage capacity and it would be:

P = V²/R or P = V * I

Hope this helps!

6 0

3 years ago

Assume the ground is uniformly level. If the horizontal component a projectile's velocity is doubled, but the vertical component

Katarina [22]

Answer:

Explanation:

Time of flight = 2 x u sinα / g where u sinα is vertical component of projectile's velocity u .

So Time of flight = 2 x vertical component / g

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g is also constant so

Time of flight will also be constant .

It will remain unchanged .

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3 years ago

A uniform rod is set up so that it can rotate about a perpendicular axis at one of its ends. The length and mass of the rod are

igor_vitrenko [27]

Answer:

0.231 N

Explanation:

To get from rest to angular speed of 6.37 rad/s within 9.87s, the angular acceleration of the rod must be

$\alpha = \frac{\theta}{t} = \frac{6.37}{9.87} = 0.6454 rad/s^2$

If the rod is rotating about a perpendicular axis at one of its end, then it's momentum inertia must be:

$I = \frac{mL^2}{3} = \frac{1.27*0.847^2}{3} = 0.303kgm^2$

According to Newton 2nd law, the torque required to exert on this rod to achieve such angular acceleration is

$T = I\alpha = 0.303*0.6454 = 0.196 Nm$

So the force acting on the other end to generate this torque mush be:

$F = \frac{T}{L} = \frac{0.196}{0.847} = 0.231 N$

4 0

3 years ago

Using a power supply, I place +1.00µC on one plate of a capacitor. A capacitor is a device for storing charge. I, then, connect

Paraphin [41]

Answer:

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5 0

3 years ago