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Daniel [21]
2 years ago
7

A gas occupies a volume of 131.0-mL at 165.2-kPa. What volume will the gas occupy at 170.8-kPa if the temperature remains the sa

me?
Chemistry
1 answer:
Ulleksa [173]2 years ago
6 0

The relationship between the pressure and the volume of the gas at a constant temperature is given by Boyle's law. The volume, of the gas at  170.8 kPa is 126.70 mL.

<h3>What is Boyle's law?</h3>

Boyle's law states the inverse relationship between the pressure and the volume of the gas. The formula for the law can be given by:

\rm P_{1}V_{1} = P_{2}V_{2}

Given,

Initial pressure = 165.2 kPa

Initial volume = 131.0 mL

Final pressure = 170.8 kPa

The final volume is calculated as:

165.2 * 131.0 = 170.8 * V

V = 126.70 mL

Therefore, the final volume of the gas is 126.70 mL.

Learn more about Boyle's law here:

brainly.com/question/16607771

#SPJ1

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The empirical formula is K₂O.

The empirical formula is the <em>simplest whole-number ratio</em> of atoms in a compound.

The <em>ratio of atom</em>s is the same as the <em>ratio of moles</em>.

So, our job is to calculate the <em>molar ratio</em> of K to O.

Step 1. Calculate the <em>moles of each element </em>

Moles of K = 32.1 g K × (1 mol K/(39.10 g K =) = 0.8210 mol K

Moles of O = 6.57 g O × (1 mol O/16.00 g O) = 0.4106 mol 0

Step 2. Calculate the <em>molar ratio of each elemen</em>t

Divide each number by the smallest number of moles and round off to an integer

K:O = 0.8210:0.4106 = 1.999:1 ≈ 2:1

Step 3: Write the <em>empirical formula </em>

EF = K₂O

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A student looks through a microscope and sees a cell that contains a cell membrane, cytoplasm, mitochondria, and lysosomes. Whic
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NO_2 + hv\rightarrow NO(g) + O(g)

The maximum wavelength of light that can cause this reaction is 420 nm.

a) The wavelength given lies in the range of visible light range that is from 400 nano meters to 700 nano meters.

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b)The maximum strength of a bond :

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c) the photodissociation reaction showing Lewis-dot structures is given in an image attached.

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