Answer:
Acceleration of the second particle at that moment is given as
Explanation:
As we know that both cars are connected by same spring
So on this system of two cars there is no external force
So we will have
now we have
now we have
so we have
Answer:
184 feets
Explanation:
Given the data:
time (sec) __ velocity (ft/sec)
0 __________30
1 __________ 54
2 __________56
3 __________34
4 __________ 8
5 __________ 2
6 __________22
Using left end approximation:
(0,1) ___ f(0) = 30
(1,2) ___ f(1) = 54
(2,3) ___f(2) = 56
(3,4) ___f(3) = 34
(4,5) ___f(4) = 8
(5,6) __ f(5) = 2
Hence, the Total distance traveled during the 6 second interval is:
Change ; dT = 1
1 * (30 + 54 + 56 + 34 + 8 + 2) = 184
Answer:
The work done by the drag force is given by 29.96 J
Explanation:
Given :
Thrust force N
Displacement m
Mass of rocket Kg
From work energy theorem,
Where thrust work gravitational work
After cutoff kinetic energy is converted into potential energy,
Put value of KE
Work done by drag force is given by,
J
Therefore, the work done by the drag force is given by 29.96 J
<span>An object is located 51 millimeters from a diverging lens the object has a height og 13 millimeters and the image height is 3.5 millimeters how far in front of the lens is image located?</span>