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adell [148]
3 years ago
14

In a classroom demonstration, the pressure inside a soft drink can is suddenly reduced to essentially zero. You may want to revi

ew (Pages 508 - 512) .Assuming the can to be a cylinder with a height of 11 cm and a diameter of 6.8 cm , find the net upward force exerted on the vertical sides of the can due to atmospheric pressure.?

Physics
1 answer:
KengaRu [80]3 years ago
4 0

Answer:

Net upward force = 2373.72N

Explanation:

The concept of Pressure = Force/Area is applied as the steps are shown in the attachment

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A 50 kg box hangs from a rope. what is the tension in the rope if
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Part a is simply mass*gravity. Tension=ma

Part b Tension= 50kg(10m/s+5.0m/s) = 750N
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The revolving nosepiece of a compound microscope is used to: a. move the condenser up or down b. change the objective lens c. ad
Jlenok [28]

Answer:

Option B: change the objective lens

Explanation:

The revolving nosepiece is one of the parts of a microscope. Its responsibility is to hold the objective lenses.

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What is the combining ratio of potassium with bromine?
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How does a seat belt counteract Newton’s law
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The angular position of objects as a function of time is given, where a, b, and care constants. In which of these cases is the a
GalinKa [24]

Answer:

Explanation:

The options is not well presented

This are the options

A. θ = at³ + b

B. θ = at² + bt + c

C. θ = at² — b

D. θ = Sin(at)

So, we want to prove which of the following option have a constant angular acceleration I.e. does not depend on time

Now,

Angular acceleration can be determine using.

α = d²θ / dt²

α = θ''(t)

So, second deferential of each θ(t) will give the angular acceleration

A. θ = at³ + b

dθ/dt = 3at² + 0 = 3at²

d²θ/dt² = 6at

α = d²θ/dt² = 6at

The angular acceleration here still depend on time

B. θ = at² + bt + c

dθ/dt = 2at + b + 0 = 2at + b

d²θ/dt² = 2a + 0 = 2a

α = d²θ/dt² = 2a

Then, the angular acceleration here is constant is "a" is a constant and the angular acceleration is independent on time.

C. θ = at² —b

dθ/dt = 2at — 0 = 2at

d²θ/dt² = 2a

α = d²θ/dt² = 2a

Same as above in B. The angular acceleration here is constant is "a" is a constant and the angular acceleration is independent on time.

D. θ = Sin(at)

dθ/dt = aCos(at)

d²θ/dt² = —a²Sin(at) = —a²θ

α = d²θ/dt² = -a²θ

Since θ is not a constant, then, the angular acceleration is dependent on time and angular displacement

So,

The answer is B and C

4 0
3 years ago
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