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adell [148]
3 years ago
14

In a classroom demonstration, the pressure inside a soft drink can is suddenly reduced to essentially zero. You may want to revi

ew (Pages 508 - 512) .Assuming the can to be a cylinder with a height of 11 cm and a diameter of 6.8 cm , find the net upward force exerted on the vertical sides of the can due to atmospheric pressure.?

Physics
1 answer:
KengaRu [80]3 years ago
4 0

Answer:

Net upward force = 2373.72N

Explanation:

The concept of Pressure = Force/Area is applied as the steps are shown in the attachment

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Answer: London Disple

Explanation:

3 0
3 years ago
Two cello strings, with the same tension and length, are played simultaneously. Their fundamental frequencies produce audible be
qwelly [4]

Explanation:

Let f₁ is the fundamental frequency, f_1=8\ Hz

Lower pitch frequency, f_2=220\ Hz

Fundamental frequency is, f_1=\dfrac{1}{2L}\sqrt{\dfrac{T}{\mu_1}}.....(1)

Lower frequency is, f_2=\dfrac{1}{2L}\sqrt{\dfrac{T}{\mu_2}}..............(2)

Dividing equation (1) and (2) as :

\dfrac{f_1}{f_2}=\sqrt{\dfrac{\mu_2}{\mu_1}}

\dfrac{\mu_2}{\mu_1}=(\dfrac{f_1}{f_2})^2

\dfrac{\mu_2}{\mu_1}=(\dfrac{8}{220})^2

\dfrac{\mu_2}{\mu_1}=0.00132

So, the ratio of  linear mass density μ of the string with the higher pitch to that of the string with the lower pitch is 0.00132. Hence, this is the required solution.

3 0
3 years ago
A water molecule consists of an oxygen atom with two hydrogen atoms bound to it. The angle between the two bonds is 106◦ . If ea
balu736 [363]

Answer:

easy 16

Explanation:

because i love jesus

3 0
3 years ago
An athlete swings a ball, connected to the end of a chain, in a horizontal circle. The athlete is able to rotate the ball at the
Andrei [34K]

Answer:

a) 2nd case rate of rotation gives the greater speed for the ball

b) 1534.98 m/s^2

c) 1515.04 m/s^2

Explanation:

(a) v = ωR

when R = 0.60, ω = 8.05×2π

v = 0.60×8.05×2π = 30.34 m/s

Now in 2nd case

when R = 0.90, ω = 6.53×2π

v = 0.90×6.53×2π = 36.92 m/s

6.35 rev/s gives greater speed for the ball.

(b) a = ω^2 R = (8.05×2π)^2 )(0.60) = 1534.98 m/s^2

(c) a = ω^2 R = (6.53×2π)^2 )(0.90) = 1515.05 m/s^2

7 0
3 years ago
A computer base unit of mass 7.5 kg is dragged along a smooth desk. If the normal contact force is 23N and the tension in the ar
kramer
<span>If there isn't any force then the normal contact force will be 


N=m*g=7.5*9.81=73.58N 

which is 73.58-23=50.58N less 

so, there the person must pull at 23 degree upward 

break down the tension in two components, vertical and horizontal. 


vertical tension= 50.58=T*sin23 

T=50.58/sin23=129.45N</span>
7 0
3 years ago
Read 2 more answers
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