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Zina [86]
3 years ago
8

Physics help me pleaseee

Physics
1 answer:
dybincka [34]3 years ago
6 0

Answer:

letter e.

Explanation:

because i know its not too deep

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Help please i really want to pass this quiz
Lesechka [4]

Answer:

It is positive and smaller in magnitude than the initial acceleration.

Explanation:

We know that acceleration is defined as the change of velocity in a given time.

We see that the time interval is equal to 30 seconds (70 - 40). In this interval we also see that the velocity increases from 245 to 250 (m/s) approximately. Therefore the acceleration is positive.

With respect to the magnitude we can say that it is smaller than at the beginning since the change of velocities is smaller with respect to the change of velocities at the beginning.

5 0
3 years ago
A vw bug is driving north on a straight two lane road at a constant 54 mph and chevy impala south at 47 on the same road (but di
mario62 [17]

Velocity of vw bug is given as

v_1 = 54 mpH towards north

velocity of imphala is given as

v_2 = 47 mph towards south

now we need to find velocity of imphala relative to bug

v_{21} = v_2 - v_1

v_{21} = 47 - (-54) = 101 mpH

so the speed is 101 mpH towards south so correct option is C

5 0
3 years ago
Which is an example of chemical energy to thermal energy?
garik1379 [7]
3. Coal burning
The coal releases chemicals when it is burned. So it is chemical to thermal.
6 0
3 years ago
Read 2 more answers
Which statements describe the image produced by a concave lens?check all that apply.
kotegsom [21]

<em>Answer:</em>

<em>The answers are: </em>

  • <em>A-which is the image is always right side up.</em>
  • <em>E-the image is virtual</em>

<em></em>

<em>Explanation: MY EXPLANATION IS YOU ARE WELCOME BIG DOG 100..</em>

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<h2 />
7 0
4 years ago
Read 2 more answers
A guitar string has a linear density of 8.30 ✕ 10−4 kg/m and a length of 0.660 m. the tension in the string is 56.7 n. when the
Sedbober [7]
Ans: Beat Frequency = 1.97Hz

Explanation:
The fundamental frequency on a vibrating string is 

f =   \sqrt{ \frac{T}{4mL} }<span>  -- (A)</span>

<span>here, T=Tension in the string=56.7N,
L=Length of the string=0.66m,
m= mass = 8.3x10^-4kg/m * 0.66m = 5.48x10^-4kg </span>


Plug in the values in Equation (A)

<span>so </span>f = \sqrt{ \frac{56.7}{4*5.48*10^{-4}*0.66} }<span> = 197.97Hz </span>

<span>the beat frequency is the difference between these two frequencies, therefore:
Beat frequency = 197.97 - 196.0 = 1.97Hz
-i</span>
3 0
4 years ago
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