Question

Find a formula for the inverse g (x) =(x-1) ^1/3-1

Answer 1

Y= x+ (x-1) ^1/3-1
y+1=x+(x-1) ^1/3
(1/3)1/3=0
y+1(1/3)= x+(x+1)
y/3=x+(x+1)
y/3=2x+1
(y/3)(2/1)=x+1
2y/3-1=x
g(x)= (2y/3-1)⁻⁻¹