Answer:
The speeds of the cars is: 0.625 miles/minute
Step-by-step explanation:
We use systems of equations in two variables to solve this problem.
Recall that the definition of speed (v) is the quotient of the distance traveled divided the time it took : 
. Notice as well that the speed of both cars is the same, but their times are different because they covered different distances. So if we find the distances they covered, we can easily find what their speed was.
Writing the velocity equation for car A (which reached its destination in 24 minutes) is:
Now we write a similar equation for car B which travels 5 miles further than car A and does it in 32 minutes:
Now we solve for 
in this last equation and make the substitution in the equation for car A:
So this is the speed of both cars: 0.625 miles/minute
Played total n games, and lostcexactly 4:
4:n-4
Option 2.
1. Simplify 7 + (12 - 9) + 7 × 3(8 - 5)
According to the Order of Operations, contents of parentheses are evaluated first. This gives
... 7 + 3 + 7 × 3 × 3
Then multiplication and division are performed left to right.
... = 7 + 3 + 21 × 3
... = 7 + 3 + 63
Followed by addition and subtraction left to right.
... = 10 + 63
... = 73
A Google search box can be relied upon to do the operations in the correct order.
_____
2. When the expression is rewritten, a different result is obtained. This is because the operations indicated by the second set of parentheses are altered.
... (7 + 12) - 9 + (7 × 3)8 - 5
... = 19 - 9 + 21 × 8 - 5
... = 19 - 9 + 168 - 5
... = 10 + 168 - 5
... = 178 - 5
... = 173
In the first expression, both +8 and -5 are multiplied by 21. In the rewritten expression, only +8 is multiplied by 21.
Answer:
2x²+5x-6 = 0
using the quadratic formula
x = 0.886 and x= -3.386
Answer: Answer Number 1; Line AB is similar to
line EF
Line BC is similar to line FG
Line CD is similar to line GH
Line DA is similar to line HE
Step-by-step explanation: First and foremost both
quadrilaterals are similar but of varying dimensions.
If we label both trapezoids as ABCD and EFGH
respectively, then it follows that the corresponding
lines (as stated in the answer above) would also be
similar.
Same applies to the four angles in the interior of the
trapezoids.
Number 2, Angle A equals Angle E
Angle B equals Angle F
Angle C equals Angle G
Angle D equals Angle H
Number 3,
If the scale factor between both figures is 2:3, then
for every length of a side in figure ABCD, the
corresponding side in figure EFGH would be
multiplied by 3/2.
Therefore if AD is 8cm, then EH equals 8 x 3/2
That gives us 12cm.
If GH is 6cm, then DC equals 6 x 2/3. That gives
us 4cm.
If AB is 3 times the length of DC, then AB equals 3
x 4, that gives us 12cm.
If AB is 12cm, then EF equals 12 x 3/2. That gives
us 18cm.
Take note that the shapes are both isosceles
trapezoids, o we have two sides of equal length, AD
and BC in the first figure and then EH and FG in the
other figure.
The first trapezoid has sides 8cm, 12cm, 8cm and
4cm. The perimeter is given as 8+12+8+4 32cm.
The second trapezoid has sides 12cm, 18cm, 12cm
and 6cm. The perimeter is given as 12+18+12+6=
48cm.
