solution:
Average velocity
Average velocity is,
Here x is the displacement and t is the time.
At the end of swimming nine length of the pool, Jack reaches the other end of pool, hence the displacement x is the length of pool, that is 25.0 m. The total time taken, t is 157.9s.
Substitute 25.0 m for x and 157.9 s for t to calculate the average velocity. The average velocity of Jack is,
v_{a} =25.0m/157.9s
v_{a} =0.158m/s
At the end of swimming ten length of the pool, Jill reaches where he started, hence the displacement x is zero. The total time taken, t is 157.9s.
Substitute 0.00 m for x and 157.9s for t to calculate the average velocity. The average velocity of Jill is,
v_{a} =0m/157.9s
v_{a}= 0m/s
The average velocity of Jack is 0.158m/s and the average velocity of Jill is 0 m/s.
Average speed
Average speed is,
Here, d is the distance travelled and t is the time.
At the end of swimming nine length of the pool, distance travelled by Jack is nine times the length of pool; that is,
The total time taken, t is 157.9s.
Substitute 225 m for d and 157.9 s for t to calculate the average speed. The average speed of Jack is,
s_{a} =225m/157.9s
1.58m/s
=1.42m/s
At the end of swimming ten length of the pool, distance travelled by Jill is ten times the length of pool; that is,
The total time taken, t is 157.9s.
Substitute 250 m for d and 157.9s for t to calculate the average speed. The average speed of Jill is,
s_{a} =250m/157.9s
1.58m/s
