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densk [106]
3 years ago
9

After a party the host pours the remnants of several bottles of wine into a jug. He then inserts a cork with a 2.25-cm diameter

into the jug, placing it in direct contact with the wine. He is amazed when he pounds the cork into place that the bottom of the jug, with a 16.5-cm diameter, breaks away. show answer No Attempt Find the force that the liquid exerts on the bottom of the bottle when the host is pounding the cork with a 150-N force. Ignore the force caused by the weight of the wine.
Physics
1 answer:
bulgar [2K]3 years ago
7 0

Answer:

F = 8066.67 N

Explanation:

The extra force exerted on the bottom of the jug can be expressed as the pressure generated by the cork multiplied by the area of the bottom. We can also obtain the Pressure P by dividing the force F1 applied to the cork by it's area A1.

Thus;

F = PA2 = (F1/A1) x (A2)

F = (F1/(πd1²/4)) x (πd2²/4)

π/4 will cancel out to give;

F = F1(d2/d1)²

F = 150(16.5/2.25)

F = 8066.67 N

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Answer: 1. 0.25 m/s squared

2. A = 0.4 m/s^2

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Think about holding a glass of cold water. Your hand is warmer than the glass. Do the particles in your hand or those in the gla
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3 years ago
Rx: hydrochloric acid 2 percent solution 500 ml. your stock solution of hydrochloric acid is 10 percent. how much of the stock s
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100 ml

100 ml of the stock solution is required to prepare the order.

We know that C1V1 = C2V2

where C1= 2%

V1 = 500ml

C2= 10%

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V2 = C1V1 / C2

     = 500 * 2% / 10%

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<h3>What is meant by stock solution?</h3>
  • A stock solution is a sizable amount of a typical reagent in a standardized concentration, like sodium hydroxide or hydrochloric acid.
  • This phrase is frequently used in analytical chemistry while doing operations like titrations where it's crucial to employ precise solution concentrations.
<h3>What distinguishes a standard solution from a stock solution?</h3>
  • The main distinction between stock solution and standard solution is that the former is a highly concentrated solution while the later is a solution whose concentration is precisely known.
  • Because standard solutions frequently arrive as stock solutions, the phrases "stock solution" and "standard solution" are connected.

To learn more about stock solution preparation visit:

brainly.com/question/14667249

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8 0
2 years ago
We would like to place an object 45.0cm in front of a lens and have its image appear on a screen 90.0cm behind the lens. What mu
liubo4ka [24]

Answer:

the radii of curvature is 30 cm.

Explanation:

given,

object is place at = 45 cm

image appears at = 90 cm

focal length = ?

refractive index = 1.5

radii of curvature = ?

\dfrac{1}{f} = \dfrac{1}{u} +\dfrac{1}{v}

\dfrac{1}{f} = \dfrac{1}{45} +\dfrac{1}{90}

f = 30 cm

using lens formula

\dfrac{1}{f} = (n-1)(\dfrac{1}{R_1} -\dfrac{1}{R_2})

R_1 = R\ and\ R_2 = -R

\dfrac{1}{f} = (n-1)(\dfrac{1}{R} +\dfrac{1}{R})

R = (n -1)\ f

R = 2(1.5 -1)\ 30

R = 30 cm

hence, the radii of curvature is 30 cm.

3 0
3 years ago
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