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densk [106]
3 years ago
9

After a party the host pours the remnants of several bottles of wine into a jug. He then inserts a cork with a 2.25-cm diameter

into the jug, placing it in direct contact with the wine. He is amazed when he pounds the cork into place that the bottom of the jug, with a 16.5-cm diameter, breaks away. show answer No Attempt Find the force that the liquid exerts on the bottom of the bottle when the host is pounding the cork with a 150-N force. Ignore the force caused by the weight of the wine.
Physics
1 answer:
bulgar [2K]3 years ago
7 0

Answer:

F = 8066.67 N

Explanation:

The extra force exerted on the bottom of the jug can be expressed as the pressure generated by the cork multiplied by the area of the bottom. We can also obtain the Pressure P by dividing the force F1 applied to the cork by it's area A1.

Thus;

F = PA2 = (F1/A1) x (A2)

F = (F1/(πd1²/4)) x (πd2²/4)

π/4 will cancel out to give;

F = F1(d2/d1)²

F = 150(16.5/2.25)

F = 8066.67 N

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An ideal spring is mounted horizontally, with its left end fixed. The force constant of the spring is 170 N/m. A glider of mass
gizmo_the_mogwai [7]

Answer:

Explanation:

First of all we shall find the velocity at equilibrium point of mass 1.2 kg .

It will be ω A , where ω is angular frequency and A is amplitude .

ω = √ ( k / m )

= √ (170 / 1.2 )

= 11.90 rad /s

amplitude A = .045 m

velocity at middle point ( maximum velocity ) = 11.9 x .045 m /s

= .5355 m /s

At middle point , no force acts so we can apply law of conservation of momentum

m₁ v₁ = ( m₁ + m₂ ) v

1.2 x .5355 = ( 1.2 + .48 ) x v

v = .3825 m /s

= 38.25 cm /s

Let new amplitude be A₁ .

1/2 m v² = 1/2 k A₁²

( 1.2 + .48 ) x v² = 170 x A₁²

( 1.2 + .48 ) x .3825² = 170 x A₁²

A₁ = .0379 m

New amplitude is .0379 m

7 0
3 years ago
James Joule (after whom the unit of energy is named) claimed that the water at the bottom of Niagara Falls should be warmer than
Molodets [167]

Answer:

0.12 K

Explanation:

height, h = 51 m

let the mass of water is m.

Specific heat of water, c = 4190 J/kg K

According to the transformation of energy

Potential energy of water = thermal energy of water

m x g x h = m x c x ΔT

Where, ΔT is the rise in temperature

g x h =  c x ΔT

9.8 x 51 = 4190 x ΔT

ΔT = 0.12 K

Thus, the rise in temperature is 0.12 K.

7 0
3 years ago
What is the weight of a 4.2 kg bowling ball on Mars?
Nataliya [291]

What is the weight of a 4.2 kg bowling ball on Mars?

Answer:

1.59 kg

Explanation:

The formula is:

<u>F = G((Mm)/r2) </u>

F is the gravitational force between two objects,

G is the Gravitational Constant (6.674×10-11 Newtons x meters2 / kilograms2),

M is the planet's mass (kg),

m is your mass (kg), and

r is the distance (m) between the centers of the two masses (the planet's radius).

Hope this helps

--Jay

8 0
3 years ago
In which way are the cathode rays deflected in the x-plates of the Cathode Ray Oscilloscope​
MrRissso [65]

Answer:

The cathode ray is deflected vertically to the fluorescent screen

Explanation:

.

4 0
3 years ago
Read 2 more answers
During a testing process, a worker in a factory mounts a bicycle wheel on a stationary stand and applies a tangential resistive
Alex

Answer:

616.223684211 N

Explanation:

F_r = Resistive force on the wheel = 115 N

F = Force acting on sprocket

r_2 = Radius of sprocket = 4.75 cm

r_1 = Radius of wheel = 25 cm

Moment of inertia is given by

I=mr_1^2\\\Rightarrow I=1.7\times 0.25^2\\\Rightarrow I=0.10625\ kgm^2

Torque

\tau=I\alpha\\\Rightarrow \tau=0.10625\times 4.9\\\Rightarrow \tau=0.520625\ Nm

Torque is given by

\tau=Fr_2-F_rr_1\\\Rightarrow F=\dfrac{\tau+F_rr_1}{r_2}\\\Rightarrow F=\dfrac{0.520625+115\times 0.25}{0.0475}\\\Rightarrow F=616.223684211\ N

The force on the chain is 616.223684211 N

5 0
3 years ago
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