Which metalloid has three valence electrons? boron arsenic silicon lithium HElp PLEase
2 answers:
Answer:
Boron
Explanation:
First, locate the metalloids on the periodic table. (First picture) The metalloids are in the yellow section. Next, remember that the group your element is in determines its valence electrons. For example, group 17/7A has 7 valence electrons. Look at the group numbers above each column on the periodic table to find out which metalloid is the answer. In this case, we need to look at 13/3A since we know that this metalloid has three valence electrons. Not all periodic tables will be labeled with the 3A part, so remember that groups 13 and over have the amount of valence electrons after you take out the one in front. For example, group 16 has 6 valence electrons because I removed the one in front of it. Now your options should be limited down to boron because we know that it is in the yellow section in group 13.
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Answer:
The total amount of energy required is 25,515.2 J.
Explanation:
Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.
When a system absorbs (or gives up) a certain amount of heat, it can happen that:
- experience a change in its temperature, which involves sensible heat,
- undergoes a phase change at constant temperature, or latent heat.
To calculate the latent heat the formula is used:
Q = m. L
Where
- Q: amount of heat
- m: mass
- L: latent heat
To calculate sensible heat the following formula is used:
Q = m. c. ΔT
where:
- Q: amount of sensible heat
- m: body mass
- c: specific heat of the substance
- ΔT: temperature range
In this case, you have in the first place a heat to raise the temp of the water from 35.0 C to 100 C, where the specific heat value for water is 4.184 :
q1 = m*c*(Tfinal-Tinitial)
q1 = 10.0 g *(4.184 )* (100 - 35.0 C) = 2719.6 J
Now you have the heat to vaporize the water, where the heat of vaporization is 2259.36 :
q2 = m*(heat of vaporization)
q2 = 10.0 g*(2259.36 ) = 22593.6 J
Finally, you have the heat to raise temp of steam to 110 C, where the specific heat value for steam is 2.02 :
q3 = m*c*(Tfinal-Tinitial)
q3 = 10.0 g*(2.02 )*(110-100 C) = 202 J
The total amount of energy can be calculated as:
Q= q1 + q2 + q3
Q= 2719.6 J + 22593.6 J + 202 J
Q=25,515.2 J
<u><em>The total amount of energy required is 25,515.2 J.</em></u>