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GrogVix [38]
3 years ago
13

What is electricity?

Physics
1 answer:
ASHA 777 [7]3 years ago
8 0

Answer:

The flow of electric charge

Explanation:

Electricity:It is defined flow of electric charge.

It is defined as the flow of charge per unit time.

Electric charge can be negative or positive .

Mathematical representation :

If charge Q flowing through the conductor and time taken in flow of charge is t seconds.

Then, current=I=\frac{Q}{t}

S.I unit of current is Ampere.It is scalar quantity.

Answer:The flow of electric charge.

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Winds transfer energy in the form heat from the air to the ground!
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The student quickly discovers that placing the marshmallow over the flame is more effective than heating the marshmallow on the
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Answer:

The answer is convection.

Explanation:

There are three types of heat transfer: conduction, convection and radiation.

  • Conduction occurs when two objects touch each other and transfer heat.
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So in this case, when the marshmallow is above the fire, it is exposed to convection, which does not occur when it is on the side of the fire.

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Explain how magnetic forces enable a maglev train to float above the tracks. Please help and hurry it’s timed
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Answer:

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3 years ago
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A 7.00 kg ball hits a 75.0 kg man standing at rest on ice. The man catches the ball. How fast does the ball need to be moving in
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<h3>Answer:</h3>

\displaystyle \overline{v_{1i}} = 35.1429 \ \frac{m}{s}

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality<u> </u>

<u>Physics</u>

<u>Momentum</u>

Momentum Formula: \overline{P} = m \overline{v}

  • P is momentum (in kg · m/s)
  • m is mass (in kg)
  • v is velocity (in m/s)

Law of Conservation of Momentum: \sum \overline{P_i} = \sum \overline{P_f}

  • States that the sum of initial momentum must equal the sum of final momentum
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[LCM] \sum \overline{P_i} = \sum \overline{P_f}  →  m_{1} \overline{v_{1i}} + m_{2} \overline{v_{2i}} = (m_{1} + m_{2}) \overline{v_{f}}

m₁ (ball) = 7.00 kg

m₂ (man) = 75.0 kg

\overline{v_{1i}} = ?

\overline{v_{2i}} = 0 \ \frac{m}{s} (man starts from rest)

\overline{v_{f}} = 3.00 \ \frac{m}{s} (the ball and the man are one mass because the man catches and <em>keeps</em> the ball)

We know no energy is lost because it is a frictionless surface. The collision should be perfectly elastic.

<u>Step 2: Solve</u>

  1. Substitute in variables [Law of Conservation of Momentum]:                    \displaystyle (7.00 \ kg) \overline{v_{1i}} + (75.0 \ kg)(0 \ \frac{m}{s}) = (7.00 \ kg + 75.0 \ kg)(3.00 \ \frac{m}{s})
  2. Multiply:                                                                                                           \displaystyle (7.00 \ kg) \overline{v_{1i}} + 0 = 246 \ kg \cdot \frac{m}{s}
  3. Simplify:                                                                                                          \displaystyle (7.00 \ kg) \overline{v_{1i}} = 246 \ kg \cdot \frac{m}{s}
  4. [Division Property of Equality] Isolate unknown:                                           \displaystyle \overline{v_{1i}} = \frac{246}{7} \ \frac{m}{s}
  5. [Evaluate] Divide:                                                                                           \displaystyle \overline{v_{1i}} = 35.1429 \ \frac{m}{s}

The initial speed of the ball should be approximately 35.14 m/s.

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