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3 years ago

A bicycle moves 3 m/s how far it will go in 30 seconds

1 answer:

5 0

The distance travelled by the bike can be calculated by using the basic relationship between speed (v), distance (S) and time (t):

$v=\frac{S}{t}$

Rearranging the equation, we get

$S=vt$

The speed of the bike is v=3 m/s, the time is t=30 s, so the distance travelled by the bike is

$S=vt=(3 m/s)(30 s)=90 m$

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PLEASE ANSWER ASAP

neonofarm [45]

Answer:

2.55sec

Explanation:

time = distance/speed = (87 m)/(34 m/s) = 2.55sec

6 0

2 years ago

A single-phase electrical load draws 600KVA at 0.6 power factor lagging. a) Find the real and reactive power absorbed by the loa

Whitepunk [10]

Answer:

(a). The reactive power is 799.99 KVAR.

(c). The reactive power of a capacitor to be connected across the load to raise the power factor to 0.95 is 790.05 KVAR.

Explanation:

Given that,

Power factor = 0.6

Power = 600 kVA

(a). We need to calculate the reactive power

Using formula of reactive power

$Q=P\tan\phi$ ...(I)

We need to calculate the $\phi$

Using formula of $\phi$

$\phi=\cos^{-1}(Power\ factor)$

Put the value into the formula

$\phi=\cos^{-1}(0.6)$

$\phi=53.13^{\circ}$

Put the value of Φ in equation (I)

$Q=600\tan(53.13)$

$Q=799.99\ kVAR$

(b). We draw the power triangle

(c). We need to calculate the reactive power of a capacitor to be connected across the load to raise the power factor to 0.95

Using formula of reactive power

$Q'=600\tan(0.95)$

$Q'=9.94\ KVAR$

We need to calculate the difference between Q and Q'

$Q''=Q-Q'$

Put the value into the formula

$Q''=799.99-9.94$

$Q''=790.05\ KVAR$

Hence, (a). The reactive power is 799.99 KVAR.

(c). The reactive power of a capacitor to be connected across the load to raise the power factor to 0.95 is 790.05 KVAR.

8 0

3 years ago

6) what is ararge of speed

irina [24]

Answer:

in everyday use and in kinematic the speed of an object is the magnitude of the change of its position it is thus a scalar quantity

5 0

3 years ago

If a one-pound weight were one foot from the pivot or shaft of a lever, how many pound-feet of force would result? A. 4 B. 1 C.

mixas84 [53]

The force is still 1 pound.

The TORQUE around the pivot is (force) x (distance from the pivot) = 1 foot-pound. (B)

8 0

3 years ago

Read 2 more answers

According to the inverse square law of light, how will the apparent brightness of an object change if its distance to us triples

aleksley [76]

According to the inverse square law of light, <span>apparent brightness will decrease by a factor of 9. Use the formula </span> $B=L/(4*pD^2)$ , to check it.

4 0

3 years ago