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nikdorinn [45]
2 years ago
7

How many lines does each stanza contain? 2 3 4 6

Physics
2 answers:
Musya8 [376]2 years ago
7 0
6 lines the stanza contains
slamgirl [31]2 years ago
4 0

Explanation:

a stanza can contain 4-6 lines or more than that, that's all upon the writer.

hope this helps you

have a great day :)

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What are the two factors that determine the period of a pendulum? acceleration of gravity and the mass of the bob mass of the bo
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<span>The two factors which determine the period of a pendulum is:

A) Length of the string
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3 years ago
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What is this process called when a liquid turns into gas
aev [14]

Answer:

evaporation

Explanation:

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3 years ago
What is the speed of sound in air at 50°F (in ft/s)?
gizmo_the_mogwai [7]

Answer:

Speed of air = 1106.38 ft/s

Explanation:

Speed of sound in air with temperature

v_{air}=331.3\sqrt{1+\frac{T}{273.15}} \\

Here speed is in m/s and T is in celcius scale.

T = 50°F

T=(50-32)\times \frac{5}{9}=10^0C \\

Substituting

v_{air}=331.3\sqrt{1+\frac{10}{273.15}}=337.31m/s \\

Now we need to convert m/s in to ft/s.

1 m = 3.28 ft

Substituting

v_{air}=337.31\times 3.28=1106.38ft/s \\

Speed of air = 1106.38 ft/s

6 0
2 years ago
A light rope is attached to a block with mass 3.60 kg that rests on a frictionless, horizontal surface. The horizontal rope pass
Readme [11.4K]

Answer and Explanation:

(a) The fre-body diagrams for each block is shown below. In the block of mass 3.60 kg, there are 3 forces acting on it: horizontal force due to the rope (F_{t}), vertical gravitational force (F_{g}) and vertical normal force (F_{n}), due to the surface. Since there is no vertical movement, F_{g} and F_{n} cancels it out. So, for this block, net force is horizontal due to the rope F_{t}.

The block of mass m is hanging from the pulley, so there is the force of the rope (F_{t}) and the gravitational force (F_{g}). Both are vertical, because there is no surface "holding" block m.

(b) Since both blocks are attached to each other, the acceleration will be the same. To calculate it, we use the Second Law of Motion:

F_{r}=m.a

a=\frac{F_{r}}{m}

a=\frac{18.8}{3.6}

a = 5.22

The acceleration of either block is 5.22 m/s².

(c) Block m has 2 forces acting on it: tension and gravitational force. Gravitational force is the force of attraction the Earth does over an object. It is calculated as the product of mass and gravitational acceleration, which has magnitude g = 9.8 m/s².

Suppose positive referential is going up. To determine mass:

F_{r}=m.a

F_{t}-F_{g}=m.a

F_{t}-m.g=m.a

18.8-9.8m=5.22m

15.02m=18.8

m = 1.25

Block m has 1.25 kg.

(d) Gravitational force is also called weight. So, as described above: F_{g}=m.g.

The weight for the hanging block is

F_{g}=1.25*9.8

F_{g}= 12.25 N

Comparing tension and weight:

\frac{12.25}{18.8} ≈ 0.65

We can see that, weight of the hanging block is almost 0.65 times smaller than the tension on the rope.

4 0
3 years ago
Assume that the speed of light in a vacuum has the hypothetical value of 18.0 m/s. A car is moving at a constant speed of 14.0 m
denis23 [38]

Answer:

4.245s

Explanation:

Given that,

Hypothetical value of speed of light in a vacuum is 18 m/s

Speed of the car, 14 m/s

Time given is 6.76 s, and we're asked to find the observed time, T

The relationship between the two times can be given as

T = t / √[1 - (v²/c²)]

The missing variable were looking for is t, and we can find it if we rearrange the formula and make t the subject

t = T / √[1 - (v²/c²)]

And now, we substitute the values and insert into the equation

t = 6.76 * √[1 - (14²/18²)]

t = 6.76 * √[1 - (196/324)]

t = 6.76 * √(1 - 0.605)

t = 6.76 * √0.395

t = 6.76 * 0.628

t = 4.245 s

Therefore, the time the driver measures for the trip is 4.245s

8 0
3 years ago
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