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3 years ago

How does a parallel circuit differ from a series circuit?

Physics

1 answer:

Levart [38]3 years ago

4 0

A series circuit has only one path for current,
while a parallel circuit has more than one.

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Which of the following is most closely related to an activated complex?

Anon25 [30]

Among the choices above, the one that is most closely related to an activated complex is the transition state. The answer is letter D. This formation forms quickly and does not stay in a way compound is. It usually forms during the enzyme – substrate reaction.

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3 years ago

The process by which hot and cold air are transferred in the atmosphere is

elena-14-01-66 [18.8K]

Hey there!

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8 0

3 years ago

Fehling's solution is added to the counters of test tube b after about 3 minutes and it turns brick red.what food substance was

hjlf

The food substance being used which turned Fehling's solution to brick red is a reducing sugar.

<h3>What is Fehling's solution?</h3>

This is an indicator which is used to test for the presence of reducing sugar or aldehydes in a solution.

Brick red precipitate of copper(I) oxide is formed when it tests positive to compounds such as glucose etc.

Read more about Fehling solution here brainly.com/question/3262179

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6 0

2 years ago

A certain superconducting magnet in the form of a solenoid of length 0.72 m can generate a magnetic field of 3.5 T in its core w

ira [324]

Answer:

55407

Explanation:

we have given that magnetic field B=3.5 T

current through the coil=90 A

Length of solenoid =0.72 m

we know the formula of magnetic field

$B=\frac{\mu _0NI}{l}$

so $N=\frac{Bl}{\mu _0I}=\frac{3.5\times 0.72}{4\pi \times 10^{-6}\times 90}=55407.277=55407\ turns$

so the number of turn in solenoid will be 55407

3 0

3 years ago

At some distance from a point charge, the electric potential is 635.0 V and the magnitude of the electric field is 189.0 N/C. Fi

Nataliya [291]

Answer:

The distance from the charge is 3.35 m.

Explanation:

Given that,

Electric potential, V = 635 V

Magnitude of electric field, E = 189 N/C

We need to find the distance from the charge. We know that the relation between electric field and electric potential is given by :

$E=\dfrac{V}{d}$

d is the distance from charge

$d=\dfrac{V}{E}\\\\d=\dfrac{635}{189}\\\\d=3.35\ m$

So, the distance from the charge is 3.35 m. Hence, this is the required solution.

8 0

3 years ago