Why are nuclear power plants controversial

An HR manager is asked to meet with upper management to discuss the

amm1812

Answer:

the answer to this question perhaps is service

3 0

3 years ago

Read 2 more answers

Given the following situation of marble in motion on rolling 10 m/s horizontally from a height of 1.5-m with negligible friction

Norma-Jean [14]

Answer:

The ball would hit the floor approximately $0.55\; \rm s$ after leaving the table.

The ball would travel approximately $5.5\; \rm m$ horizontally after leaving the table.

(Assumption: $g = 9.81\; \rm m \cdot s^{-2}$ .)

Explanation:

Let $\Delta h$ denote the change to the height of the ball. Let $t$ denote the time (in seconds) it took for the ball to hit the floor after leaving the table. Let $v_0(\text{vertical})$ denote the initial vertical velocity of this ball.

If the air resistance on this ball is indeed negligible: $\displaystyle \Delta h = -\frac{1}{2}\, g\, t^{2} + v_0(\text{vertical}) \cdot t$ .

The ball was initially travelling horizontally. In other words, before leaving the table, the vertical velocity of the ball was $v_0(\text{vertical}) = 0 \; \rm m \cdot s^{-1}$ .

The height of the table was $1.5\; \rm m$ . Therefore, after hitting the floor, the ball would be $1.5\; \rm m \!$ below where it was before leaving the table. Hence, $\Delta h = -1.5\;\rm m$ .

The equation becomes:

$\displaystyle -1.5 = -\frac{9.81}{2} \, t^{2}$ .

Solve for $t$ :

$\displaystyle t = \sqrt{1.5 \times \frac{2}{9.81}} \approx 0.55$ .

In other words, it would take approximately $0.55\; \rm s$ for the ball to hit the floor after leaving the table.

Since the air resistance on the ball is negligible, the horizontal velocity of this ball would be constant (at $v(\text{horizontal}) =10\; \rm m \cdot s^{-1}$ ) until the ball hits the floor.

The ball was in the air for approximately $t = 0.55\; \rm s$ and would have travelled approximately $v(\text{horizontal})\cdot t \approx 5.5\;\rm m$ horizontally during the flight.

4 0

2 years ago

A 12 kg barrel is pulled up by a rope. The barrel accelerates at 1.2 m/s2. Find the force exerted by the rope. Show all your wor

IgorLugansk [536]

Answer:

F = 132N

Explanation:

Let the pulling force be F

Given the mass of the barrel is 12 Kg and The acceleration is 1.2 m/ $sec^2$

We know that Net Force = $mass\times acceleration$

Now net force = F - mg

F - mg = ma

F = mg + ma

F = m(a+g) = $12\times (1.2 +9.8)=132N$

Note that there will be a downward force acting on the body which is equal to mg

3 0

3 years ago

describe the charge, mass and the location of each subatomic particle and the role each plays in determining the properties of a

Harrizon [31]

Explanation :

An atom is a smallest particle of matter. An atom consists of protons, neutrons and electrons. These are three subatomic particles.

Protons are positively charged species while neutrons are negatively charged species. Electrons revolves around an atom.

Charge :

The charge of an electron is negative or $-1.6\times 10^{-19} \ C$

The charge of proton is +e or $1.6\times 10^{-19} \ C$

Neutron has no charge.

Mass :

Atomic mass of electron is $9.1\times10^{-31}\ Kg$

Atomic mass of proton is $1.67\times10^{-27}\ Kg$

Atomic mass of neutron is $1.67\times10^{-27}\ Kg$

Both protons and neutrons are located inside the nucleus at the center.

Charge, atomic mass and location determines the properties of an atom. Atomic mass tells about the number of protons and neutrons inside an atom. Electric charge tells us the number of electrons gain or lost.

6 0

2 years ago

An all-electric car (not a hybrid) is designed to run from a bank of 12.0 V batteries with total energy storage of 2.30 ✕ 107 J.

AnnyKZ [126]

Answer:

a) $I=733.33\ A$