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JulijaS [17]
3 years ago
11

Which element would have properties most similar to those of fluorine (F) ?

Physics
2 answers:
aalyn [17]3 years ago
8 0
I think the answer is cholorine
qaws [65]3 years ago
7 0

Answer:

chlorine

Explanation:

because fluorine is halogen so also chlorine which has the same chemical properties similar to fluorine

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water in a cup and a kettle can have the same temperature even though the quantities are different . give reasons​
jekas [21]

Answer:

The reason is because both are exposed to a virtually infinite heat sink, due to the virtually infinite mass  and of the surrounding environment, compared to the sizes of either the cup or the kettle such that the equilibrium temperature, T_{(equilibrium)} reached is the same for both the cup and the kettle as given by the relation;

\infty M_{(environ)} \times  c_{(environ)} \times (T_2 - T_1) = m_{1} \times  c_{(water)} \times (T_3 - T_2) + m_{2} \times  c_{(water)} \times (T_4 - T_2)

Due to the large heat sink, T₂ - T₁ ≈ 0 such that the temperature of the kettle and that of the cup will both cool to the temperature of the environment

Explanation:

4 0
3 years ago
Review
sleet_krkn [62]

Answer:

yes

Explanation:

8 0
3 years ago
Read 2 more answers
Help! <br><br><br>I'm not sure my answer is correct.<br><br><br>Problem is attached!​
kaheart [24]
  • Let G be xN

\\ \sf\longmapsto x-20=30

\\ \sf\longmapsto x=30+20

\\ \sf\longmapsto x=50N

Option B

3 0
2 years ago
Read 2 more answers
A motorbike is travelling with a velocity of 3m/s. It accelerates at a rate of 9.3m/s for 1.8s. Calculate the distance it travel
Misha Larkins [42]

Explanation:

Consider the kinematic equation,

x  = vt +  \frac{1}{2} a {t}^{2}

where x is the distance traveled, v is the initial velocity, a is the acceleration and t is time. By plugging in known values and solving for x,

x = 3(1.8) +  \frac{1}{2} (9.3) {1.8}^{2}

through simple algebra we get

x = 20.466

where this is the distance traveled in meters.

4 0
3 years ago
An airplane is pushed 22 degrees eastward off its northward course by a jet stream traveling at a speed of 136.73 km/hr. The new
uranmaximum [27]

As the speed of airplane is change due to jet stream

So the net speed is given as

v_{net} = v_{plane} + v_{stream}

now we can rearrange it as

v_{plane} = v_{net} - v_{stream}

now by the formula of vector difference we have

v_{plane} = \sqrt{v_{net}^2 + v_{stream}^2 - 2v_{net}v_{stream}cos\theta}

now plug in all values

v_{plane} = \sqrt{365^2 + 136.73^2 - 2* 365* 136.73*cos22}[tex]v_{plane} = 243.7 km/hr

so above is the speed of the plane

3 0
3 years ago
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