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3 years ago

Which element would have properties most similar to those of fluorine (F) ?

Physics

2 answers:

aalyn [17]3 years ago

8 0

I think the answer is cholorine

qaws [65]3 years ago

7 0

Answer:

chlorine

Explanation:

because fluorine is halogen so also chlorine which has the same chemical properties similar to fluorine

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An RLC circuit has a resistance of 200 Ω and an inductance of 15 mH. Its oscillation frequency is 7000 Hz. At time t = 0, the cu

MArishka [77]

Answer: 2.13 × 10^-4 A

Explanation:

Given that the RLC circuit has a resistance R = 200 Ω and an inductance L = 15 mH.

Its oscillation frequency F = 7000 Hz

The initial current I = 25 mA = 25/1000 or 25 × 10^-3 A

Since there is no charge on the capacitor, the current after complete 5 circle will be achieved by using the formula in the attached file.

Please find the attached file for the remaining explanation for the solution.

8 0

3 years ago

78. A film of oil on water will appear dark when it is very thin, because the path length difference becomes small compared with

Hoochie [10]

To solve this problem it is necessary to apply the concepts related to the condition of path difference for destructive interference between the two reflected waves from the top and bottom of a surface.

Mathematically this expression can be described under the equation

$\delta = 2nt$

Where

n = Refractive index

t = Thickness

In terms of the wavelength the path difference of the reflected waves can be described as

$\delta = \frac{\lambda}{4}$

Where

\lambda = Wavelenght

Equation the two equations we have that

$2nt = \frac{\lambda}{4}$

$t = \frac{\lambda}{8n}$

Our values are given as

$\lambda = 380nm \rightarrow$ Wavelength of light

$n = 1.4$

$t = \frac{380nm}{8*1.4}$

$t = 33.93nm$

Therefore the minimum thickness of the oil for destructive interference to occur is approximately 34.0 nm

4 0

3 years ago

Calculate the number of free electrons per cubic meter for some hypothetical metal, assuming that there are 1.3 free electrons p

boyakko [2]

Answer:

The number of free electrons per cubic meter is $7.61\times 10^{28}\ m^{-3}$

Explanation:

It is given that,

The number of free electrons per cubic meter is, 1.3

Electrical conductivity of metal, $\sigma=6.8\times 10^7\ \Omega^{-1}m^{-1}$

Density of metal, $\rho=10.5\ g/cm^3$

Atomic weight, A = 107.87 g/mol

Let n is the number of free electrons per cubic meter such that,

$n=1.3\ N$

$n=1.3(\dfrac{\rho N_A}{A})$

Where

$\rho$ is the density of silver atom

$N_A$ is the Avogadro number

A is the atomic weight of silver

$n=1.3\times (\dfrac{10.5\ g/cm^3\times 6.02\times 10^{23}\ atoms/mol}{107.87\ g/mol})$

$n=7.61\times 10^{22}\ cm^{-3}$

$n=7.61\times 10^{28}\ m^{-3}$

Hence, this is the required solution.

6 0

3 years ago

Six seconds after starting from rest, a car is moving at 15 m/s. What is the car's

Sidana [21]

Answer:

2.5 m/s²

Explanation:

a = ∆v/∆t = (15 m/s)/(6 s) = (15/6) m/s² = 2.5 m/s²

7 0

3 years ago

Describe what’s going on in position-time graphs 1 , 3, &5

Verizon [17]

Answer:

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7 0

3 years ago