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Brilliant_brown [7]
3 years ago
15

A ball is ejected to the right with an unknown horizontal velocity from the top of a pillar that is 50 meters in height. At the

exact instant, a carriage moving on rails is also released to the right from the bottom of the pillar. Calculate the velocity with which the carriage should be released so that the ball falls in the carriage after the carriage has traveled a distance of 50 meters on the ground.
A. 12.20 meters/ seconds
B. 13.23 meters/ seconds
C. 14.30 meters/ seconds
D. 15.65 meters/ seconds**
E. 16.00 meters/ seconds

I believe D is right = 15.65m/s
Also ** on Plato
Physics
2 answers:
jeka943 years ago
5 0
D!!!!!!! Is the correct one ....!!!!!! ...
Illusion [34]3 years ago
3 0

Answer:

D. 15.65 meters/ seconds**

Explanation:

You're correct. Use kinematic equation to find V_final.

{v}^{2}  =  {v 0}^{2}  + 2a(xf - x0)

Then use the following to find time.

t = (vf - v0) \div a

Then 50m/3.2s = 15.65m/s

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a train is moving 35m/s to the east. it speeds up to 42 m/s east over the course of 40 seconds. what is the trains acceleration?
lianna [129]

Answer:

0.175 m/s²

Explanation:

Given:

v₀ = 35 m/s

v = 42 m/s

t = 40 s

Find: a

v = at + v₀

42 m/s = a (40 s) + 35 m/s

a = 0.175 m/s²

7 0
3 years ago
Any push or pull on an object is Question 5 options: Acceleration Velocity Force Inertia
Kobotan [32]
This would be force. Acceleration is increasing the speed in an object and velocity is how fast an object is going. Also, inertia basically says that an object will stay at rest or in motion unless an outside force acts on it. So, for example, a ball will stay in the air unless gravity acts on it and pulls it down. By definition, force is any action, unopposed (or by itself without any other forces that would do the opposite) will change the motion of an object, so this definitely makes the most sense for the question. Hope this helps!
8 0
3 years ago
Read 2 more answers
What effort force will be required to lift the 20 N object using the pulley above?
Umnica [9.8K]

Answer:

I think it is 5N.

Explanation:

4 0
3 years ago
Light travels at 300,000,000 m/s. This is an example
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3 0
3 years ago
A rocket, initially at rest on the ground, accelerates straight upward from rest with constant acceleration 58.8m/s2 . The accel
Zanzabum
Split the operation in two parts. Part A) constant acceleration 58.8m/s^2, Part B) free fall.

Part A)
Height reached, y = a*[t^2] / 2 = 58.8 m/s^2 * [7.00 s]^2 / 2 = 1440.6 m

Now you need the final speed to use it as initial speed of the next part.

Vf = Vo + at = 0 + 58.8m/s^2 * 7.00 s = 411.6 m/s

Part B) Free fall

Maximum height, y max ==> Vf = 0

Vf = Vo - gt ==> t = [Vo - Vf]/g = 411.6 m/s / 9.8 m/s^2 = 42 s

ymax = yo + Vo*t - g[t^2] / 2

ymax = 1440.6 m + 411.6m/s * 42 s - 9.8m/s^2 * [42s]^2 /2
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Answer: ymax = 10084.2m
8 0
3 years ago
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