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ANEK [815]
3 years ago
8

A car is driving directly north on the freeway at a speed of 91 km/h and a truck is leaving the freeway driving 56 km/h in a dir

ection that is 28° west of north. What is the velocity of the truck relative to the car? Please report the answer with a positive angle.
Physics
1 answer:
Sladkaya [172]3 years ago
3 0

Answer:

v = 49.69 km/hr

Explanation:

velcoity of truck with respect to car is given as = velocity of truck - velocity of car

velcoity of truck with respect to car is given as = (-54 sin(28)i +54cos(28)j - 91km/h

                                                                              = -24.35i - 43.32j

magnitude of velocity is

v = \sqrt{ 24.35^2+43.32^2}

v = 49.69 km/hr

the direction is

tan^{-}[\frac{ 43.32}{24.35}]

= 60.65 degree towrd south of west

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A straight trail with a uniform inclination of 15 degrees leads from a lodge at an elevation of 600 feet to a mountain lake at a
9966 [12]

Answer:

The length of the trail = 22796 ft

Explanation:

From the ΔABC

AC = length of the trail = x

AB = 6100 - 600 = 5500 ft

Angle of inclination \theta = 15°

\sin \theta = \frac{AB}{AC}

\sin 15 = \frac{5900}{x}

x = \frac{5900}{0.2588}

x = 22796 ft

Since x = AC = Length of the trail.

Therefore the length of the trail = 22796 ft

7 0
2 years ago
Two objects that are not initially in thermal equilibrium are placed in close contact. After a while, the temperature of the cod
Dima020 [189]

Answer:

If the temperature of  the colder object rises by the same amount as the temperature of the hotter object drops, then <u>the specific heats of both objects will be equal.</u>

Explanation:

If the temperature of  the colder object rises by the same amount as the temperature of the hotter object drops when the two<u> objects of same mass</u> are brought into contact, then their specific heat capacity is equal.

<u>We can prove this by the equation of heat for the two bodies:</u>

<em>According to given condition,</em>

\Delta T_1=\Delta T_2

\frac{Q_1}{m_1.c_1} = \frac{Q_2}{m_2.c_2}

<em>when there is no heat loss from the system of two bodies then </em>Q_1=Q_2

\frac{1}{m.c_1} =\frac{1}{m.c_2}

\Rightarrow c_1=c_2

  • Thermal conductivity is ultimately affects the rate of heat transfer, however the bodies will attain their final temperature based upon their mass and their specific heat capacities.

The temperature of the colder object will rise twice as much as the temperature of the hotter object only in two cases:

  • when the specific heat of the colder object is half the specific heat of the hotter object while mass is equal for both.

OR

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3 0
2 years ago
A person pushes a refrigerator across a horizontal floor. The mass of the refrigerator is 110 kg, the coefficient of static fric
Law Incorporation [45]

Answer:

Explanation:

mass of refrigerator, m = 110 kg

coefficient of static friction, μs = 0.85

coefficient of kinetic friction, μk = 0.59

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F = μs x mg

F = 0.85 x 110 x 9.8

F = 916.3 N

(b) The force required to move the refrigerator with constant speed

F' = μk x mg

F' = 0.59 x 110 x 9.8

F' = 636.02 N

(c) Let a be the acceleration.

Net force = Applied force - friction force

F net = 950 - 636.02

F net = 313.98 N

a = F net / mass

a = 313.98 / 110

a = 2.85 m/s²

4 0
3 years ago
If Jerome is swinging on a rope and transferring energy from gravitational potential energy to kinetic energy, A)compression B)w
Gnesinka [82]
Salutations!

If Jerome is swinging on a rope and transferring energy from gravitational potential energy to kinetic energy,  _______________ is being done.

<span>If Jerome is swinging on a rope and transferring energy from gravitational potential energy to kinetic energy, work is being done. Energy being transferred and the object begins to move is called work.

Thus, your answer is option B.

Hope I helped (:

Have a great day!</span>
7 0
3 years ago
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Vlad [161]
Humid air has higher pressure because of the heaviness of the water
7 0
3 years ago
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