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ANEK [815]
4 years ago
8

A car is driving directly north on the freeway at a speed of 91 km/h and a truck is leaving the freeway driving 56 km/h in a dir

ection that is 28° west of north. What is the velocity of the truck relative to the car? Please report the answer with a positive angle.
Physics
1 answer:
Sladkaya [172]4 years ago
3 0

Answer:

v = 49.69 km/hr

Explanation:

velcoity of truck with respect to car is given as = velocity of truck - velocity of car

velcoity of truck with respect to car is given as = (-54 sin(28)i +54cos(28)j - 91km/h

                                                                              = -24.35i - 43.32j

magnitude of velocity is

v = \sqrt{ 24.35^2+43.32^2}

v = 49.69 km/hr

the direction is

tan^{-}[\frac{ 43.32}{24.35}]

= 60.65 degree towrd south of west

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the triceps muscle in the back of the upper arm extends the forearm. this muscle in a professional boxer exerts a force of 2.00×
Alexus [3.1K]

Answer: 0.512 kgm²

Explanation:

Given

Force, F = 2*10^3 N

Angular acceleration, α = 121 rad/s²

Lever arm, r(⊥) = 3.1 cm = 3.1*10^-2 m

τ = r(⊥) * F

Also,

τ = Iα

Using the first equation, we have

τ = r(⊥) * F

τ = 0.031 * 2*10^3

τ = 62 Nm

Now we calculate for the inertia using the second equation

τ = Iα, making I subject of formula, we have

I = τ / α, on substituting, we have

I = 62 / 121

I = 0.512 kgm²

Thus, the moment of inertia of the boxers forearm is 0.512 kgm²

5 0
4 years ago
What is measured in watts that starts with a p
Nesterboy [21]
Power is measured in watts
6 0
3 years ago
A crate hangs from a ring at the middle of a rope, as the drawing illustrates. a person is pulling on the right end of the rope
aev [14]

Answer:

No

Explanation:

In order for the rope to be perfectly horizontal, there must be a vertical component in tension

5 0
2 years ago
A policeman investigating an accident measures the skid marks left by a car on the horizontal road. He determines that the dista
sleet_krkn [62]
<h2>The velocity of car was m m/s </h2>

Explanation:

When the car skids , its centripetal force is provided by frictional force .

Here centripetal force F = \frac{mv^2}{r}

here v is the velocity of car and r is the radius of the curve .

The frictional force f = μ R

here μ is the coefficient of kinetic friction and R is normal reaction

Thus f =  m g

On horizontal road R = mg

Thus F = f  at the time of skid .

Thus v = \sqrt{\mu rg}

= \sqrt{0.29x23.74x10} = 9 m/s

3 0
3 years ago
A long-distance runner is running at a constant speed of 5 m/s.
vivado [14]

Answer:

3.33 minutes (3 minutes and 20 seconds)

Explanation:

Speed of the runner = s = 5 m/s

We need to calculate how will it take for runner to complete 1 km. We have the speed, the distance and we need to find the time. Before performing any calculations, we must convert the values to same units.

Speed is in m/s and distance is in kilometers. So we have to either convert speed to km/s or distance into meters. In this case, converting distance into meters would be a convenient option.

1 kilo meters = 1000 meters

The distance, speed and time are related by the equation:

Distance = Speed x Time

So,

Time = Distance/Speed

Using the values, we get:

t = 1000/5

t = 200 seconds

This means, the runner can complete 1 kilometers in 200 seconds. Since, there are 60 seconds in a minute, we can convert this time to minutes, by dividing it by 60. i.e.

200 \text{ sec} = \frac{200}{60} \text{ min} = 3.33 \text{ min}

Thus, it will take the runner 3.33 minutes (3 minutes and 20 seconds) to travel 1 km.

3 0
3 years ago
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