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ANEK [815]
3 years ago
8

A car is driving directly north on the freeway at a speed of 91 km/h and a truck is leaving the freeway driving 56 km/h in a dir

ection that is 28° west of north. What is the velocity of the truck relative to the car? Please report the answer with a positive angle.
Physics
1 answer:
Sladkaya [172]3 years ago
3 0

Answer:

v = 49.69 km/hr

Explanation:

velcoity of truck with respect to car is given as = velocity of truck - velocity of car

velcoity of truck with respect to car is given as = (-54 sin(28)i +54cos(28)j - 91km/h

                                                                              = -24.35i - 43.32j

magnitude of velocity is

v = \sqrt{ 24.35^2+43.32^2}

v = 49.69 km/hr

the direction is

tan^{-}[\frac{ 43.32}{24.35}]

= 60.65 degree towrd south of west

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Two buses are driving along parallel freeways that are 5mi apart, one heading east and the other heading west. Assuming that eac
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Answer:

101.54m/h

Explanation:

Given that the buses are 5mi apart, and that they are both driving at the same speed of 55m/h, rate of change of distance can be determined using differentiation as;

Let l be the be the distance further away at which they will meet from the current points;

l=\sqrt{13^2-5^2}=12m\\\\\frac{dl}{dt}=-(55m/h+55m/h})\\\\=-110m/h#The speed toward each other.

\frac{dh}{dt}=0, \ \ \ \ h=constant\\\\h^2+l^2=b^2\\\\2h\frac{dh}{dt}+2l\frac{dl}{dt}=2b\frac{db}{dt}\\\\2\times5\times0+2\times12\times(-110)=2\times13\frac{db}{dt}\\\\\frac{db}{dt}=-101.54m/h

Hence, the rate at which the distance between the buses is changing when they are 13mi apart is 101.54m/h

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2 years ago
On the Moon's surface, lunar astronauts placed a corner reflector, off which a laser beam is periodically reflected. The distanc
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4.88 x 10∧-8 sec

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How society has been benefited by the knowledge of physics​
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Read 2 more answers
A passenger jet travels from Los angles to Bombay, India, in 22 h. The return flight takes 17 h. The difference in flight times
Hoochie [10]

Answer:

70.5 mph

Explanation:

A passenger jet travels from Los Angeles to Bombay, India, in 22h.

The return flight takes 17 h.

The difference in flight times is caused by winds over the Pacific Ocean that

blow primarily from west to east.

If the jet's average speed in still air is 550 mi/h what is the average speed

of the wind during the round trip flight? Round to the nearest mile per hour.

Is your answer reasonable?

:

Let w = speed of the wind

:

Write a distance equation (dist is the same both ways

17(550+w) = 22(550-w)

9350 + 17w = 12100 - 22w

17w + 22w = 12100 - 9350

39w = 2750

W = 2750/39

w = 70.5 mph seems very reasonable

:

Confirming if the solution by finding the distances using these value

17(550+70.5) = 10549 mi

22(550-70.5) = 10549 mi; confirms our solution of w = 70.5 mph

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3 years ago
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