A box of books weighing 325 N moves at a constant velocity across the floor when the box is pushed with a force of 425 N exerted
1 answer:
Answer:
Mu,k between the floor and the box is 0.609
Explanation:
given information:
weight of the book, W = 325 N
applied force, F = 425 N
angle, θ = 35.2°
to find the coefficient kinetic between the floor and the box, wee need to calculate the horizontal and vertical force.
first we calculate the vertical force, there are weight, normal force(N) and applied vertical force.
according to Newton's first law
ΣF = 0
Σ = 0
W - N + F sin θ = 0
N = W + F sin θ
Next, we calculate the force in horizontal direction. applied force and friction force()
Σ = 0
F cos θ - = 0
F cos θ - μk (W - F sin θ) = 0
μk = (F cos θ) / (W + F sin θ)
= (425 cos 35.2°)/(325+425 sin 35.2°)
= 0.609
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Answer:
1. Largest force: C; smallest force: B; 2. ratio = 9:1
Explanation:
The formula for the force exerted between two charges is
where K is the Coulomb constant.
q₁ and q₂ are also identical and constant, so Kq₁q₂ is also constant.
For simplicity, let's combine Kq₁q₂ into a single constant, k.
Then, we can write
1. Net force on each particle
Let's
- Call the distance between adjacent charges d.
- Remember that like charges repel and unlike charges attract.
Define forces exerted to the right as positive and those to the left as negative.
(a) Force on A
(b) Force on B
(C) Force on C
(d) Force on D
(e) Relative net forces
In comparing net forces, we are interested in their magnitude, not their direction (sign), so we use their absolute values.
2. Ratio of largest force to smallest
