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Dominik [7]
3 years ago
14

A small first-aid kit is dropped by a rock climber who is descending steadily at -1.25 m/s. After 2.5 seconds, what is the veloc

ity of the first aid kit and how far is the kit below the climber?
Physics
1 answer:
postnew [5]3 years ago
7 0
The genuine answer here

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A car accelerates at a rate of 3 m/s^2. If its original speed is 8 m/s, how many seconds will it take the car to reach a final s
kkurt [141]

Answer:

\Large \boxed{\mathrm{5.67 \ seconds }}

Explanation:

\displaystyle \mathrm{acceleration \ = \ \frac{final \ velocity - initial \ velocity }{elapsed \ time}}

\displaystyle A \ = \ \frac{V_f - V_i }{t}

\displaystyle 3 \ = \ \frac{25 - 8 }{t}

\displaystyle 3 \ = \ \frac{17 }{t}

\displaystyle t \ = \ \frac{17 }{3} \approx 5.67

4 0
3 years ago
A 150 kg car hits a wall with 45 N of force, what was its acceleration?​
alisha [4.7K]

Answer:

a = 0.3 m/s²

Explanation:

Given: 45 N, 150 kg

To find: a

Formula: a = \frac{F}{m}

Solution: To find a, divide the force by the weight  

A = F ÷ m

=  45 ÷  150

= 0.3 m/s²

Newtons are derived units, equal to 1 kg-m/s². In other words, a single Newton is equal to the force needed to accelerate one kilogram one meter per second squared.

4 0
3 years ago
If the angle of reflection is 82 and the light ray strikes a flat mirror, what will the angle
il63 [147K]

Answer:

82

Explanation:

According to law of reflection, the angle of incidence = angle of reflection

4 0
3 years ago
Read 2 more answers
Which of the following determines whether light shining on a metal surface will eject electrons from that surface?
PtichkaEL [24]
From that list, only the frequency makes the difference.

Einstein won his only Nobel Prize for his explanation of this effect.
8 0
3 years ago
11. A car is pulled with a force of 10,000 N. The car's mass is 1267 kg. But, the car covers 394.6 m in 15 seconds.
aleksklad [387]

Answer:

A) a = 7.89 m/s²

B) a = 3.51 m/s²

C) 4.38 m/s²

D) Frictional force

E) F_f = 5552.83 N

Explanation:

A) Formula for Force is;

F = ma

Where;

m is mass

a is acceleration

We are given;

F = 10,000 N

m = 1267 kg

Thus;

10000 = 1267a

a = 10000/1267

a = 7.89 m/s²

B) We are told the car covers 394.6 m in 15 seconds.

Using Newton's third equation equation of motion, we can find the actual acceleration.

s = ut + ½at²

u is zero since the object began from rest.

Thus;

S = ½at²

394.6 = ½ × a × 15²

a = 394.6 × 2/225

a = 3.51 m/s²

C) difference in accelerations = 7.89 - 3.51 = 4.38 m/s²

D) The force that caused the difference in acceleration is frictional force

E) To find the magnitude of the force that caused the difference in acceleration, we will use the formula;

F - F_f = ma

F_f = F - ma

Where F_f is the frictional force

Thus;

F_f = 10000 - 1267(3.51)

F_f = 5552.83 N

7 0
3 years ago
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