Answer:
Angular velocity (w) = 8.86 rad/s
Explanation:
Angular velocity (w) = 
g= 9.81 m/s
R= 0.5
hi (initial depth) = 0.5m
Hence=
= 8.86 rad/s
Answer:
2. [B] = [L]/[T] and [C] = [L]/[T]
Explanation:
I assume you mean this:
A = B² + 2B⁴/C²
Since you can't add numbers with different units (for example, you can't add seconds to meters), each term in the sum must have the same units as A.
B² = [L]²/[T]²
B = [L]/[T]
B⁴/C² = [L]²/[T]²
C²/B⁴ = [T]²/[L]²
C² = B⁴ [T]²/[L]²
C² = ([L]/[T])⁴ [T]²/[L]²
C² = [L]²/[T]²
C = [L]/[T]
Notice we ignore the 2 coefficient, which is unitless.
Explanation:
003 (part 1 of 2)
Pressure is force divided by area.
P = F / A
P = (117 kg × 9.8 m/s²) / (2 × (0.05 m)²)
P = 229,320 Pa
003 (part 2 of 2)
There are approximately 6895 Pa in 1 psi.
P = 229,320 Pa × (1 psi / 6895 Pa)
P = 33.3 psi
004 (part 1 of 2)
Since the collisions are elastic, the angle of reflection is the same as the angle of incidence (it bounces off at the same angle).
Impulse = change in momentum
F Δt = m Δv
F (36 s) = (300 × 0.003 kg) (5.2 sin 57° m/s − (-5.2 sin 57° m/s))
F = 0.218 N
004 (part 2 of 2)
Pressure is force over area.
P = F / A
P = 0.218 N / 0.712 m²
P = 0.306 N/m²
Answer:
the image can be rather real or virtual
The sun's intensity for an outer planet located at a distance 6r from the sun is 5.55 W/m². The result is obtained by using the inverse square law formula.
<h3>What is the Inverse Square Law formula?</h3>
The Inverse Square Law formula describes the intensity of light is inversely proportional to the square of the distance. It can be expressed as

Where
- I₁ = Intensity at distance 1 (W/m²)
- I₂ = Intensity at distance 2 (W/m²)
- d₁ = distance 1 from a light source (m)
- d₂ = distance 2 from a light source (m)
Given the case the sun's intensity is 200 W/m² for an inner planet at the distance r. If an outer planet is at a distance 6r, what is the sun's intensity?
By using the inverse square law formula, the sun's intensity for an outer planet is




I₂ = 5.55 W/m²
Hence, the sun's intensity for a planet at a distance 6r from the sun is 5.55 W/m².
Learn more about intensity of light here:
brainly.com/question/13155277
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