I think the correct answer is
D) Ted associated being asked a question with embarrassment.
Glad I could help, and good luck!
AnonymousGiantsFan
Answer: 40.84 m
Explanation:
Given
Radius of the disk, r = 2m
Velocity of the disk, v = 7 rad/s
Acceleration of the disk, α = 0.3 rad/s²
Here, we use the formula for kinematics of rotational motion to solve
2α(θ - θ•) = ω² - ω•²
Where,
ω• = 0
ω = v/r = 7/2
ω = 3.5 rad/s
2 * 0.3(θ - θ•) = 3.5² - 0
0.6(θ - θ•) = 12.25
(θ - θ•) = 12.25 / 0.6
(θ - θ•) = 20.42 rad
Since we have both the angle and it's radius, we can calculate the arc length
s = rθ = 2 * 20.42
s = 40.84 m
Thus, the needed distance is 40.84 m
Answer:800N
Explanation:
Force of repulsion = kq1q2/r^2
Q1= 20*10^-6
Q2=100*10^-6
R=150cm=0.15m
K= 9*10^9
F= 2*10^-5*1*10^-4*9*10^9/(0.15)^2
F= 2*1*9*10^-5-4+9/(0.15)^2
F= 18*10^0/(0.15)^2
F=18/0.0225
F=800N
A = 15, B = 1
48 + 15 = 63 for the first 86km
43 - 1 = 42 for the remaining 54 km
time = distance/speed
t1 = 86/63 = 1.3651hours
t2 = 54/42 = 1.2857hours
speed = distance/time
s = 140/2.6508
average speed = 52.8km/h
