Explanation:
The runner runs for a total time of
\Delta t=10.0 min= 600 sΔt=10.0min=600s
The energy converted by the runner during this time is equal to the power of the runner times the total time:
E=P \Delta t=400 W \cdot 600 s =2.4 \cdot 10^5 JE=PΔt=400W⋅600s=2.4⋅10
5
J
<span>The weight lifted by a machine to the applied force on a machine is called mechanical advantage.
This is written as Mechanical advantage, M. A, = load(weight)/effort.
So for 1) M.A = 2 and load = 2, 000lb = 8896.446N.
So 2 = 8896.446/ effort
Effort = 8896.446/2 = 4448.48
Similarly for M.A of 2, 000, 000 we have
Effort = 8896.446/ 2, 000, 000 = 0.004448</span>
A and c
do not complete the circuit there is no battery on a and paper dose not conduct electricity
Answer:
Explanation:
Given
mass of projectile 
initial horizontal speed 
height 
Considering vertical motion
velocity gained by projectile during 26.7 m motion
v=final velocity
u=initial velocity
a=acceleration
s=displacement
Horizontal velocity will remain same as there is no acceleration
final velocity 
Initial kinetic Energy 
Final Kinetic Energy 
Work done by all the force is equal to change in kinetic Energy of object
Work done by gravity is 
