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4 years ago

Help please I’m stuck on thsi question

Chemistry

2 answers:

Ira Lisetskai [31]4 years ago

8 0

The answer is B and I have to add this so I can submit the answer

vodomira [7]4 years ago

7 0

Since it’s asking for chemical to thermal, B.

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Please help with this lab !

vekshin1

To get out the iron filings put everything in to a container and then put the magnet to the side to attract them. Pull them out of the container. Then, I don’t know how to separate the sand and salt. Maybe evaporate the salt? I joke you can figure it out. Best of luck! :)

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3 years ago

Convert 1.25 atm to bar.

Tasya [4]

Answer: 1.27 bar

Explanation:

1 atm = 1.01325 bar

1.25 atm = Z (let Z be the unknown value)

To get the value of Z, cross multiply

Z x 1 atm = 1.25 atm x 1.01325 bar

1 atm•Z = 1.2665625 atm•bar

To get the value of Z, divide both sides by 1 atm

1 atm•Z/1 atm = 1.2665625 atm•bar/1atm

Z = 1.2665625 bar

(Round up Z to the nearest hundredth as 1.27 bar)

Thus, 1.25 atm when coverted gives 1.27 bar

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3 years ago

Naftalin buharlaşırsa hangi olay gerçekleşir?<br><br>ACİLLLLLL!

Eduardwww [97]

Answer:

Turkish: Bir gaza dönüşecekler ve gaz, güveler ve güve larvaları için çok zehirlidir.

English:They will turn in to a gass and the gass is very toxic to moths and moth larvae.

6 0

3 years ago

RATE LAW QUESTION !

vivado [14]

In general, we have this rate law express.:

$\mathrm{Rate} = k \cdot [A]^x [B]^y$
we need to find x and y

ignore the given overall chemical reaction equation as we only preduct rate law from mechanism (not given to us).

then we go to compare two experiments in which only one concentration is changed

compare experiments 1 and 4 to find the effect of changing [B]
divide the larger [B] (experiment 4) by the smaller [B] (experiment 1) and call it Δ[B]

Δ[B]= 0.3 / 0.1 = 3

now divide experiment 4 by experient 1 for the given reaction rates, calling it ΔRate:

ΔRate = 1.7 × 10⁻⁵ / 5.5 × 10⁻⁶ = 34/11 = 3.090909...

solve for y in the equation $\Delta \mathrm{Rate} = \Delta [B]^y$

$3.09 = (3)^y \implies y \approx 1$

To this point, $\mathrm{Rate} = k \cdot [A]^x [B]^1$

do the same to find x.
choose two experiments in which only the concentration of B is unchanged:

Dividing experiment 3 by experiment 2:
Δ[A] = 0.4 / 0.2 = 2
ΔRate = 8.8 × 10⁻⁵ / 2.2 × 10⁻⁵ = 4

solve for x for $\Delta \mathrm{Rate} = \Delta [A]^x$

$4= (2)^x \implies x = 2$

the rate law is

Rate = k·[A]²[B]

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3 years ago

Why are solutions considered mixtures?

Alex_Xolod [135]

Solute and solvent form a solution, which means two different kinds of molecules/atoms/compounds are mixed together, therefore, it is a mixture.

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3 years ago