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2 years ago

Help please I’m stuck on thsi question

Chemistry

2 answers:

Ira Lisetskai [31]2 years ago

8 0

The answer is B and I have to add this so I can submit the answer

vodomira [7]2 years ago

7 0

Since it’s asking for chemical to thermal, B.

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State the oxidation number assigned to each bold element in the formula: NH4+1 a 3 b -3 c -1 d 6

Leya [2.2K]

The fomula is NH4 (1+)

There are only two elements N and H.

As per oxidation state rules, the most electronegative element will have a negative oxidation state and the other element will have a positive oxidation state.

N is more electronative than H, so H will have a positive oxidation state and nitrogen will have a negative oxidation state.

You can also use the rule that states the hydrogen mostly has 1+ oxidation state,except when it is bonded to metals.

In conclusion the oxidation state of H in NH4 (1+) is 1+.

Now you must know that the sum of the oxidations states equals the charge of the ion, which in this case is 1+.

That implies that 4* (1+) + x = 1+

=> x = (1+) - 4(+) = 3-

Answer: the oxidation state of N is 3-, that is the option b.

8 0

3 years ago

How much space does a 246g box take up. Its density is listed at 3.2 g/cm3.

CaHeK987 [17]

Answer:

76.875 cm3

<h2>Explanation:</h2>

Since: Density = $\frac{Mass}{volume\\}$

Then: Volume = $\frac{Mass}{Density\\}$

The mass of the box = 246g

and the density = 3.2 g/cm3

Then: The volume = $\frac{246}{3.2}$

= 76.875 cm3

4 0

2 years ago

A buffer consists of 0.45 M CH3COOH (acetic acid) and 0.35 M CH3COONa. The Ka of acetic acid is 1.8 x 10-5 . a) Calculate the pH

Zigmanuir [339]

Answer:

A) pH of Buffer solution = 4.59

B) pH after 5.0 ml of 2.0 M NaOH have been added to 400 ml of the original buffer solution = 4.65

Explanation:

This is the Henderson-Hasselbalch Equation:

$pH = pKa + log\frac{[conjugate base]}{[acid]}$

to calculate the pH of the following Buffer solutions.

8 0

2 years ago

Can anybody check my answer?

anzhelika [568]

Answer:

$\boxed{\text{25. 20 L; 26. 49 K}}$

Explanation:

25. Boyle's Law

The temperature and amount of gas are constant, so we can use Boyle’s Law.

$p_{1}V_{1} = p_{2}V_{2}$

Data:

$\begin{array}{rcrrcl}p_{1}& =& \text{100 kPa}\qquad & V_{1} &= & \text{10.00 L} \\p_{2}& =& \text{50 kPa}\qquad & V_{2} &= & ?\\\end{array}$

Calculations:

$\begin{array}{rcl}100 \times 10.00 & =& 50V_{2}\\1000 & = & 50V_{2}\\V_{2} & = &\textbf{20 L}\\\end{array}\\\text{The new volume will be } \boxed{\textbf{20 L}}$

26. Ideal Gas Law

We have p, V and n, so we can use the Ideal Gas Law to calculate the volume.

pV = nRT

Data:

p = 101.3 kPa

V = 20 L

n = 5 mol

R = 8.314 kPa·L·K⁻¹mol⁻¹

Calculation:

101.3 × 20 = 5 × 8.314 × T

2026 = 41.57T

$T = \dfrac{2026}{41.57} = \textbf{49 K}\\\\\text{The Kelvin temperature is }\boxed{\textbf{49 K}}$

6 0

2 years ago

Potential energy is what

____ [38]

Answer:

the energy possessed by a body by its value of its position relative to others, stresses within itself, electric charge, and other factors.

Explanation:

4 0

1 year ago