The correct answer is
D. Groups and Families
I did the quiz nd this was the right answer
Hopes this helps :)
pshyical change is a usually reversible change of a substance, as size or shape: Freezing a liquid is a physical change. Compare chemical change.
internal change is when the movement of the particles increases
specific latent heat is the amount of energy per kg (unit mass) required to change ice to water without change in temperature.
To solve the problem it is necessary to apply the concepts related to the voltage in a coil, through the percentage relationship that exists between the voltage and the number of turns it has.
So things our data are given by
![N_1 = 160](https://tex.z-dn.net/?f=N_1%20%3D%20160)
![N_2 = 1400](https://tex.z-dn.net/?f=N_2%20%3D%201400)
![\Delta V_{1rms} = 62V](https://tex.z-dn.net/?f=%5CDelta%20V_%7B1rms%7D%20%3D%2062V)
PART A) Since it is a system in equilibrium the relationship between the two transformers would be given by
![\frac{N_1}{N_2} = \frac{\Delta V_{1rms}}{\Delta V_{2rms}}](https://tex.z-dn.net/?f=%5Cfrac%7BN_1%7D%7BN_2%7D%20%3D%20%5Cfrac%7B%5CDelta%20V_%7B1rms%7D%7D%7B%5CDelta%20V_%7B2rms%7D%7D)
So the voltage for transformer 2 would be given by,
![\Delta V_{2rms} = \frac{N_2}{N_1} \Delta V_{1rms}](https://tex.z-dn.net/?f=%5CDelta%20V_%7B2rms%7D%20%3D%20%5Cfrac%7BN_2%7D%7BN_1%7D%20%5CDelta%20V_%7B1rms%7D)
PART B) To express the number value we proceed to replace with the previously given values, that is to say
![\Delta V_{2rms} = \frac{N_1}{N_2} \Delta V_{1rms}](https://tex.z-dn.net/?f=%5CDelta%20V_%7B2rms%7D%20%3D%20%5Cfrac%7BN_1%7D%7BN_2%7D%20%5CDelta%20V_%7B1rms%7D)
![\Delta V_{2rms} = \frac{1400}{160} 62V](https://tex.z-dn.net/?f=%5CDelta%20V_%7B2rms%7D%20%3D%20%5Cfrac%7B1400%7D%7B160%7D%2062V)
![\Delta V_{2rms} = 1446.66V](https://tex.z-dn.net/?f=%5CDelta%20V_%7B2rms%7D%20%3D%201446.66V)
A) Work energy relation;
Work =ΔKE ; work done = Force × distance, while, Kinetic energy = 1/2 MV²
F.s = 1/2mv²
F× 4×10^-2 = 1/2 × 5 ×10^-3 × (600)²
F = 900/0.04
= 22500 N
Therefore, force is 22500 N
b) From newton's second law of motion;
F = Ma
Thus; a = F/m
= 22500/(5×10^-3)
= 4,500,000 m/s²
But v = u-at
0 = 600- 4500,000 t
t = 1.33 × 10^-4 seconds