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mart [117]
3 years ago
14

Could You Take 2 Elements From The Periodic Table Of Elements, and possibly make one of other 116 elements that are on the table

? And by the way, just to check, how many elements are there on The Periodic Table Of Elements?
Physics
2 answers:
Elanso [62]3 years ago
7 0
They said you were retated
LekaFEV [45]3 years ago
5 0
That's what stars do all the time. 
For example, in the sun (and MOST other stars), deep down in the center
of the sun's core, two atoms of Hydrogen get squashed together so hard
that they blend into one atom of Helium AND release some energy. 
That's where the sun's energy all comes from.  It's called "nuclear fusion". 
It needs tremendous temperature and pressure to happen.  We know how
to do it, but we can't control it.  So far, the only thing we've ever been able
to use it for is Hydrogen bombs.   

There are 92 elements on the Periodic Table that are found in nature,
plus another 20 or so that have been made in the laboratory, but only
a few atoms of them.
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viva [34]
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5 0
3 years ago
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Compute the density in g/cm^3 of a piece of metal that had mass of 0.485 kg and a volume of 52cm^3
steposvetlana [31]

Answer:

9.3 g/cm³

Explanation:

First, convert kg to g:

0.485 kg × (1000 g / kg) = 485 g

Density is mass divided by volume:

D = (485 g) / (52 cm³)

D = 9.33 g/cm³

Rounding to two significant figures, the density is 9.3 g/cm³.

8 0
3 years ago
A stiff wire 32.5 cm long is bent at a right angle in the middle. One section lies along the z axis and the other is along the l
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Explanation:

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4 0
3 years ago
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4 0
2 years ago
Two long, parallel wires carry currents of different magnitudes. if the amount of current in each wire is doubled, what happens
Mrac [35]
The force per unit of length between two wires carrying current is
\frac{F}{L}= \frac{\mu_0 I_1 I_2}{2 \pi r}
where I1 and I2 are the currents in the two wires, while r is the distance between them.

We can see from the formula that the force is proportional to the product between I1 and I2: F \sim I_1 I_2
so, if we double both I1 and I2, we get a factor 4:
F' \sim (2I_1 )(2I_2)=4 I_1 I_2 =4 F
so, the force between the wires will be 4 times the original value.
4 0
3 years ago
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