There is no movement in line C and the greatest velocity occurs at line D. The answers are:
1. 0.5 m/s
2. 0.25 m/s
3. 14m and -2m
4. -1 m/s
<h3>
What is Position - time Graph ?</h3>
Position time graph is the graph of distance or displacement against time. The slope of the graph is velocity.
The given positions of four objects as a function of time are shown
on the graph to the right.
1.) The velocity of object A will be the slope m of the line A.
Slope m = Δx / Δt
m = (4 - 0) / (8 - 0)
m = 4 / 8
m = 0.5 m/s
Velocity at A = 0.5 m/s
2.) The average velocity of object B will be the slope m of the line B.
Slope m = Δx / Δt
m = (6 - 4) / (8 - 0)
m = 2 / 8
m = 0.25 m/s
The average velocity of object B is 0.25s
3.) The object moved a total distance during the first eight seconds will be 4m for A, 2m for B, and 8m for D
Total distance = 4 + 2 + 8 = 14m
It’s net displacement during the same time will be 2. That is,
Displacement = 8 - 6 = -2m
4.) The greatest speed occurred at line D. The velocity of the object moving at the greatest speed will be the slope of the line D
V = -Δx / Δt
V = -8/8
V = -1 m/s
Therefore, there is no movement in line C and the greatest velocity occurs at line D.
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Answer:
66.375 x 10⁻⁶ C/m
Explanation:
Using Gauss's law which states that the net electric flux (∅) through a closed surface is the ratio of the enclosed charge (Q) to the permittivity (ε₀) of the medium. This can be represented as
;
∅ = Q / ε₀ -----------------(i)
Where;
∅ = 7.5 x 10⁵ Nm²/C
ε₀ = permittivity of free space (which is air, since it is enclosed in a bag) = 8.85 x 10⁻¹² Nm²/C²
Now, let's first get the charge (Q) by substituting the values above into equation (i) as follows;
7.5 x 10⁵ = Q / (8.85 x 10⁻¹²)
Solve for Q;
Q = 7.5 x 10⁵ x 8.85 x 10⁻¹²
Q = 66.375 x 10⁻⁷ C
Now, we can find the linear charge density (L) which is the ratio of the charge(Q) to the length (l) of the rod. i.e
L = Q / l ----------------------(ii)
Where;
Q = 66.375 x 10⁻⁷ C
l = length of the rod = 10.0cm = 0.1m
Substitute these values into equation (ii) as follows;
L = 66.375 x 10⁻⁷C / 0.1m
L = 66.375 x 10⁻⁶ C/m
Therefore, the linear charge density (charge per unit length) on the rod is 66.375 x 10⁻⁶ C/m.
Answer:
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