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3 years ago

Whenever possible, these types of power plants should be built because they generate virtually no pollution. (2 points)

1 answer:

8 0

Wind farms, solar collectors, and nuclear power plants generate no pollution.

But wind farms make noise, wind and solar are both hazardous to birds, and there's no known means of disposing of nuclear plant waste that's completely safe.

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A fire woman dropped a person onto the safety net. Right

dolphi86 [110]

Answer:

m = 28.7[kg]

Explanation:

To solve this problem we must use the definition of kinetic energy, which can be calculated by means of the following equation.

$E_{k}=\frac{1}{2}*m*v^{2}\\$

where:

Ek = kinetic energy = 1800 [J]

m = mass [kg]

v = 11.2 [m/s]

$1800=\frac{1}{2}*m*(11.2)^{2}\\m = 28.7[kg]$

7 0

2 years ago

How many total atoms in the chemical formula CaCO2?

Gre4nikov [31]

Explanation:

Calcium carbonate is a molecule that contains one atom of calcium, one atom of carbon, and three atoms of oxygen.

7 0

3 years ago

Why, on a sunny day, it is normally hot inside a greenhouse

Dahasolnce [82]

Because of the greenhouse gases inside the greenhouse, and the gases trap the heat from the sun so the plant don't freeze, hope this helps

5 0

3 years ago

The specific heat capacity of water is 4.184 J/(g.˚C). How much thermal energy is required to change the temperature of 700.0g o

worty [1.4K]

Answer:

Should be 145854.24J or:

145.9 KJ

Explanation:

I did the calculations

4 0

2 years ago

An emf of 22.0 mV is induced in a 519-turn coil when the current is changing at the rate of 10.0 A/s. What is the magnetic flux

zhenek [66]

Answer:

$\phi=1.56\times 10^{-5}\ Wb$

Explanation:

Given that,

Emf, V = 22 mV

Number of turns in the coil us 519

Rate of change of current is 10 A/s.

We need to find the magnetic flux through each turn of the coil at an instant when the current is 3.70 A.

Let's find the inductance first. So,

$L=\dfrac{\epsilon}{(dI/dt)}\\\\L=\dfrac{0.022}{10}\\\\L=0.0022\ H$

We have,

$L=\dfrac{N\phi}{I}$ , $\phi$ is magnetic flux

$\phi=\dfrac{LI}{N}\\\\\phi=\dfrac{0.0022\times3.7}{519}\\\\\phi=1.56\times 10^{-5}\ Wb$

So, the magnetic flux is $1.56\times 10^{-5}\ Wb$ .

8 0

2 years ago