Answer:
![g_{moon}=1.67 [m/s^{2} ]](https://tex.z-dn.net/?f=g_%7Bmoon%7D%3D1.67%20%5Bm%2Fs%5E%7B2%7D%20%5D)
Explanation:
The weight of some mass is defined as the product of mass by gravitational acceleration. In this way using the following formula we can find the weight.
where:
w = weight [N]
m = mass = 0.06 [kg]
g = gravity acceleration = 10 [N/kg]
Therefore:
![w=0.06*10\\w=0.6[N]](https://tex.z-dn.net/?f=w%3D0.06%2A10%5C%5Cw%3D0.6%5BN%5D)
By Hooke's law we know that the force in a spring can be calculated by means of the following expression.
where:
k = spring constant [N/m]
x = deformed distance = 6 [cm] = 0.06 [m]
We can find the spring constant.
![k= F/x\\k=0.6/0.06\\k=10 [N/m]](https://tex.z-dn.net/?f=k%3D%20F%2Fx%5C%5Ck%3D0.6%2F0.06%5C%5Ck%3D10%20%5BN%2Fm%5D)
Since we use the same spring on the moon and the same mass, the constant of the spring does not change, the same goes for the mass.
![F_{moon}=k*0.01\\F = 10*0.01\\F=0.1[N]](https://tex.z-dn.net/?f=F_%7Bmoon%7D%3Dk%2A0.01%5C%5CF%20%3D%2010%2A0.01%5C%5CF%3D0.1%5BN%5D)
Since this force is equal to the weight, we can now determine the gravitational acceleration.
![F=m*g_{moon}\\g=F/m\\g = 0.1/0.06\\g_{moon} = 1.67[m/s^{2} ]](https://tex.z-dn.net/?f=F%3Dm%2Ag_%7Bmoon%7D%5C%5Cg%3DF%2Fm%5C%5Cg%20%3D%200.1%2F0.06%5C%5Cg_%7Bmoon%7D%20%3D%201.67%5Bm%2Fs%5E%7B2%7D%20%5D)
Answer:
14.167 m/s
Explanation:
Average speed = Total distance/Total time taken.
Average speed = 170/12 - 0 = 170/12 = 14.167 m/s
From the point of view of an observer located on the Earth - no.
Australia has the OPTUS satellites on the geostationary orbits.
In comparing the Ptolemaic system to the Copernican system, neither is entirely correct since Ptolemy said the earth was at the center and Copernicus said <span>the planets had circular orbits. This is correct</span>
Answer:
Explanation:
for earth -sun system
E = σ T⁴ , E is radiation emitted by sun at temperature T
E = 4π R₁² x solar constant on earth , R₁ is distance between earth and sun.
for marsh -sun system
E = σ T⁴ , E is radiation emitted by sun at temperature T
E = 4π R₂² x solar constant on Mars , R₂ is distance between earth and sun.
from two equation ,
4π R₂² x solar constant on Mars = 4π R₁² x solar constant on earth
solar constant on Mars = (R₁ / R₂ )² x solar constant on earth
