1.6456 x 10^3 (ten to the third power)
Configuration of carbon is 1s2 2s2 2p2 and the rest of all is correct
MgSO4, CO2, AlCl3 are the answer
Answer:
Mass = 5.92 g
Explanation:
Given data:
Volume of O₂ = 4.15 mol
Temperature and pressure = standard
Mass in gram = ?
Solution:
The given problem will be solve by using general gas equation,
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
By putting values,
1 atm × 4.15L = n ×0.0821 atm.L /mol.K × 273.15 k
4.15 atm.L = n ×22.43 atm.L /mol
n = 4.15 atm.L / 22.43 atm.L /mol
n = 0.185 mol
Mass in gram:
Mas = number of moles × molar mass
Mass = 0.185 mol ×32g/mol
Mass = 5.92 g
