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Mariana [72]
3 years ago
12

ShoppingBay is an online auction service that requires several reports. Data for each auctioned item includes an ID number, item

description, length of auction in days, and minimum required bid. Design a flowchart or pseudocode for the following:
a. A program that accepts data for one auctioned item. Display data for an auction only if the minimum required bid is over $100.00.
b. A program that continuously accepts auction item data until a sentinel value is entered and displays all data for auctions in which the minimum required bid is over $100.00.
c. A program that continuously accepts auction item data and displays data for every auction in which there are no bids yet (in other words, the minimum bid is $0.00) and the length of the auction is one day or less.
d. A program that continuously accepts auction data and displays data for every auction in which the length is between 7 and 30 days inclusive.
e. A program that prompts the user for a maximum required bid, and then continuously accepts auction data and displays data for every auction in which the minimum bid is less than or equal to the amount entered by the user.

Engineering
1 answer:
daser333 [38]3 years ago
5 0

Answer:

START

  READ ID_Number

  READ Item_description

  READ length_of_auction_Days

  READ minimum_required_bid  

  IF minimum_required_bid GREATER THAN 100

      THEN

          DISPLAY

              Item Details are

              Item Id : ID_Number

              Item Description: Item_description

              Length Action days: length_of_auction_Days

              Minimum Required Bid: minimum_required_bid

END

Explanation:

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A strain gauge with a 5 mm gauge length gives a displacement reading of 1.25 um. Calculate the stress value given by this displa
KengaRu [80]

Answer:

stress  = 50MPa

Explanation:

given data:

Length of strain guage is 5mm

displacement\delta = 1.25 \mu m =\frac{1.25}{1000} =  0.00125 mm

stress due to displacement in structural steel can be determined by using following relation

E =\frac{stress}{strain}

stress = E \times strain

where E is young's modulus of elasticity

E for steel is 200 GPa

stress = 200\times 10^3 *\frac{1.25*10^{-3}}{5}

stress  = 50MPa

7 0
3 years ago
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Answer:

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5 0
2 years ago
The snowmobile has a weight of 250 lb, centered at G1, while the rider has a weight of 150 lb, centered at G2. Ifh=3ft, determin
KATRIN_1 [288]

Answer:

See explaination

Explanation:

Please kindly check attachment for the step by step solution of the given problem.

5 0
3 years ago
Would be much appreciated if someone could help with this will give brainiest.
Mashcka [7]

Answer:   both mm and inches on each dimension in a sketch (with the main dimension in one format and the other in brackets below it), in the way you can have dual dimensions shown when detailing an idw view.

personally think it would look a mess/cluttered with even more text all over the sketch environment, but everyone's differenent.

If it's any help - you know you can enter dimensions in either format?  If you're working in mm you can still dimension a line and type "2in" and vice-versa.  Probably know this already, but no harm saying it, just in case.

You can enter the units directly in or mm and Inventor will convert to current document settings (which  you can change - maybe someone can come up with a simple toggle icon to toggle the document settings).  Tools>Document Settings>Units

Unlike SolidWorks when you edit the dimension the original entry shows in the dialog box so it makes it easy to keep track of different units even if they aren't always displayed.  (SWx does the conversion or equation and then that is what you get.)

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4 0
3 years ago
Here, we want to become proficient at changing units so that we can perform calculations as needed. The basic heat transfer equa
netineya [11]

Answer:

9500 kJ; 9000 Btu

Explanation:

Data:

m = 100 lb

T₁ = 25 °C

T₂ = 75 °C

Calculations:

1. Energy in kilojoules

ΔT = 75 °C - 25 °C = 50 °C  = 50 K

m = \text{100 lb} \times \dfrac{\text{1 kg}}{\text{2.205 lb}} \times \dfrac{\text{1000 g}}{\text{1 kg}}= 4.54 \times 10^{4}\text{ g}\\\\\begin{array}{rcl}q & = & mC_{\text{p}}\Delta T\\& = & 4.54 \times 10^{4}\text{ g} \times 4.18 \text{ J$\cdot$K$^{-1}$g$^{-1}$} \times 50 \text{ K}\\ & = & 9.5 \times 10^{6}\text{ J}\\ & = & \textbf{9500 kJ}\\\end{array}

2. Energy in British thermal units

\text{Energy} = \text{9500 kJ} \times \dfrac{\text{1 Btu}}{\text{1.055 kJ}} = \text{9000 Btu}

7 0
3 years ago
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