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r-ruslan [8.4K]
3 years ago
5

A diffraction pattern forms when light passes through a single slit. The wavelength of the light is 691 nm. Determine the angle

that locates the first dark fringe when the width of the slit is (a) 3.8 × 10-4 m and (b) 3.8 × 10-6 m.
Physics
1 answer:
expeople1 [14]3 years ago
7 0

Explanation:

Given that,

Wavelength of the light, \lambda=691\ nm=691\times 10^{-9}\ m

(a) Slit width, a=3.8\times 10^{-4}\ m

The angle that locates the first dark fringe is given by :

sin\theta=\dfrac{\lambda}{a}

sin\theta=\dfrac{691\times 10^{-9}}{3.8\times 10^{-4}}

\theta=0.104^{\circ}

(b) Slit width, a=3.8\times 10^{-6}\ m

The angle that locates the first dark fringe is given by :

sin\theta=\dfrac{\lambda}{a}

sin\theta=\dfrac{691\times 10^{-9}}{3.8\times 10^{-6}}

\theta=10.47^{\circ}

Hence, this is the required solution.

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