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Lena [83]
3 years ago
5

What is the force of gravity (from the Earth) on the 700kg satellite if it’s 10km above the Earths surface?

Physics
1 answer:
joja [24]3 years ago
3 0

Answer:

The force of gravity on a 700 kg satellite if its 10 km above Earth's surface is given by

    = {\frac{(6.674\times 10^{-11}N. m^2/kg^2)(5.97\times 10^{24}kg) }{(10\times10^3)^2} = 3984378 m / s^{2}

Explanation:

The force of gravity on a 700 kg satellite if its 10 km above Earth's surface is given by

    = {\frac{(6.674\times 10^{-11}N. m^2/kg^2)(5.97\times 10^{24}kg) }{(10\times10^3)^2} = 3984378 m / s^{2}

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<h2>The seagull's approximate height above the ground at the time the clam was dropped is 4 m</h2>

Explanation:

We have equation of motion s = ut + 0.5 at²

        Initial velocity, u = 0 m/s

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     Substituting

                      s = ut + 0.5 at²

                      s = 0 x 3 + 0.5 x 9.81 x 3²

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The seagull's approximate height above the ground at the time the clam was dropped is 4 m

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What would happen if both the radius and mass of a planet were cut in half
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Explanation:

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3 years ago
on an unknown temperature scale, the freezing point of water is -15°U and the boiling point is +60°U. develop a linear conversio
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Answer:

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If F = 32 then U = -15 and

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Check: let F = 212

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Explanation:

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