Question

What is the force of gravity (from the Earth) on the 700kg satellite if it’s 10km above the Earths surface?

Answer 1

Answer:

The force of gravity on a 700 kg satellite if its 10 km above Earth's surface is given by

    = ${\frac{(6.674\times 10^{-11}N. m^2/kg^2)(5.97\times 10^{24}kg) }{(10\times10^3)^2}$ = 3984378 m / $s^{2}$

Explanation:

The force of gravity on a 700 kg satellite if its 10 km above Earth's surface is given by

    = ${\frac{(6.674\times 10^{-11}N. m^2/kg^2)(5.97\times 10^{24}kg) }{(10\times10^3)^2}$ = 3984378 m / $s^{2}$