How many calories are required to raise the temperature of 75g of water from 20 ˚C to 50˚ C?

Identify the element oxidized, the element reduced, the oxidizing agent, and the reducing agent for the following equation

bazaltina [42]

The element that gains electrons, becomes reduced.

While the one which loses electrons, becomes oxidized.

In this equation,

CH₃OH + Cr₂O₇²⁻---- --> CH₂O + Cr³⁺.

By balancing the equation, we will get:

3CH₃OH + Cr₂O₇²⁻ + 8H⁺ --> 3CH₂O + 2Cr³⁺ + 7H₂O

Here the oxidation state of Cr changes from +6 to +3 that is it is being reduced thus serving as a oxidizing agent while other element retain their charges.

Here Cr₂O₇²⁻ is reduced while CH₃OH is oxidized.

So Cr₂O₇²⁻ serves as a oxidizing agent, while CH₃OH serves as reducing agent .

4 0

2 years ago

Can someone help me? -just check my latest question.. thanks...

Harman [31]

Explanation:

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${\boxed{ \fbox{ \fbox{ \fbox{ \pink{hello}}}}}}$

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬ $\mathscr \fcolorbox{blue}{green}{BE \: BRAINLY}$ ▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬ $\mathscr \fcolorbox{blue}{blue}{BE \: BRAINLY}$ ▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬ $\mathscr \fcolorbox{blue}{red}{BE \: BRAINLY}$ ▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬ $\mathscr \fcolorbox{blue}{gray}{BE \: BRAINLY}$ ▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬

$\mathscr \fcolorbox{blue}{pink}{BE \: BRAINLY}$

7 0

2 years ago

How many neutrons are present in a nucleus whose atomic number is one and whose mass number is one?

nekit [7.7K]

Because the proton has a mass of 1 and a neutron has a mass of 1, we know that there is exactly one proton in the nucleus (because of the atomic number) which therefore tells us there are no neutrons as adding one would make the mass more than one.

8 0

2 years ago

Sighting along the C2-C3 bond of 2-methylbutane, the least stable conformation (Newman projection) has a total energy strain of

natima [27]

Answer:

21 KJ/mol

Explanation:

For this question, we have to start with the linear structure of 2-methylbutane. With the linear structure, we can start to propose all the Newman projections keep it in mind that the point of view is between carbons 2 and 3 (see figure 1).

Additionally, we have several energy values for each interaction present in the Newman structures:

-) Methyl-methyl gauche: 3.8 KJ/mol

-) Methyl-H eclipse: 6.0 KJ/mol

-) Methyl-methyl eclipse: 11.0 KJ/mol

-) H-H eclipse: 4.0 KJ/mol

Now, we can calculate the energy for each molecule.

Molecule A

In this molecule, we have 2 Methyl-methyl gauche interactions only, so:

(3.8x2) = 7.6 KJ/mol

Molecule B

In this molecule, we have a Methyl-methyl eclipse interaction a Methyl-H eclipse interaction and an H-H eclipse interaction, so:

(11)+(6)+(4) = 21 KJ/mol

Molecule C

In this molecule, we have 1 Methyl-methyl gauche interaction only, so:

3.8 KJ/mol

Molecule D

In this molecule, we have three Methyl-H eclipse interaction, so:

(6*3) = 18 KJ/mol

Molecule E

In this molecule, we have 1 Methyl-methyl gauche interaction only, so:

3.8 KJ/mol

Molecule F

In this molecule, we have a Methyl-methyl eclipse interaction a Methyl-H eclipse interaction and an H-H eclipse interaction, so:

(11)+(6)+(4) = 21 KJ/mol

The structures with higher energies would be less stable. In this case, structures B and F with an energy value of 21 KJ/mol (see figure 2).

I hope it helps!

3 0

3 years ago

If it takes 5 hours to produce 8.0 kg of alcohol, how any days will it take to consume 1000 kg of glucose?

Ipatiy [6.2K]

It takes 21.3 days

<h3>Further explanation</h3>

Given

5 hr = 8 kg Alcohol

Required

Days to consume 1000 kg of glucose

Solution

Alcoholic fermentation⇒ glucose produces ethanol and carbon dioxide,

C₆H₁₂O₆ → 2 C₂H₅OH + 2CO₂

mol ethanol :

$\tt \dfrac{5000~g}{46~g/mol}=108.7~moles$

moles of glucose to produce 108.7 moles ethanol :

$\tt \dfrac{1}{2}\times 108.7=54.35$

54.35 moles = 5 hours

moles of 1000 kg of glucose :

$\tt \dfrac{10^6~g}{180~g/mol}=5555.5~moles$

So for 5555.5 moles, it takes :

$\tt \dfrac{5555.5}{54.35}\times 5~hours=511.085~h=21.3~days$

7 0

3 years ago