All categories

3 years ago

Which compound is most reactive, ethene, ethane, or ethyne?

Chemistry

2 answers:

Stels [109]3 years ago

8 0

The answer is: ethyne

vredina [299]3 years ago

3 0

Answer:

Ethyne is more suitable answer.

Explanation:

Among all the three, alkanes are least reactive, as they have all the saturated bonds between carbon carbon atoms. They have no polarity in them.

Alkenes have one pi bond between two carbon atoms while alkynes have two pi bonds between two carbons.

The pi bond is easy to break, so generally we consider that due to two pi bonds alkyne are more reactive than alkenes.

However, it should be noted that in electrophilic addition reaction, alkene are more reactive than alkynes.

You might be interested in

How many moles of oxygen are present in 16 g of oxygen gas

makkiz [27]

Hope this helps

Answer- 1 mole

4 0

3 years ago

Read 2 more answers

A helium balloon with a volume of 5.0 L and a pressure of 105 kPa at 25°C floats up high in the sky where the pressure is 850 mm

aalyn [17]

Answer:

volume 2- 4.011 L

8 0

3 years ago

16.

mixas84 [53]

Answer:

Explanation:

When going from top to bottom in any group of the periodic table, the atomic radius always tends to increase

8 0

2 years ago

_______ particles move very fast and freely. A.Gas B.Solid C.Liquid

inn [45]

The answer is A. Gas particles!

6 0

3 years ago

What is the mass of a sample of metal that is heated from 58.8°C to 88.9°C with a

Vadim26 [7]

Answer:

$\boxed {\boxed {\sf 333 \ grams}}$

Explanation:

We are asked to find the mass of a sample of metal. We are given temperatures, specific heat, and joules of heat, so we will use the following formula.

$Q= mc \Delta T$

The heat added is 4500.0 Joules. The mass of the sample is unknown. The specific heat is 0.4494 Joules per gram degree Celsius. The difference in temperature is found by subtracting the initial temperature from the final temperature.

ΔT= final temperature - initial temperature

The sample was heated from 58.8 degrees Celsius to 88.9 degrees Celsius.

ΔT= 88.9 °C - 58.8 °C = 30.1 °C

Now we know three variables:

Q= 4500.0 J
c= 0.4494 J/g°C
ΔT = 30.1 °C

Substitute these values into the formula.

$4500.0 \ J = m (0.4494 \ J/g \textdegree C)(30.1 \textdegree C)$

Multiply on the right side of the equation. The units of degrees Celsius cancel.

$4500.0 \ J = m (13.52694 J/g)$

We are solving for the mass, so we must isolate the variable m. It is being multiplied by 13.52694 Joules per gram. The inverse operation of multiplication is division, so we divide both sides by 13.52694 J/g

$\frac {4500.0 \ J }{13.52694 J/g}= \frac{m (13.52694 J/g)}{13.52694 J/g}$

The units of Joules cancel.

$\frac {4500.0 \ J }{13.52694 J/g}= m$

$332.6694729 \ g =m$

The original measurements have 5,4, and 3 significant figures. Our answer must have the least number or 3. For the number we found, that is the ones place. The 6 in the tenth place tells us to round the 2 up to a 3.

$333 \ g \approx m$

The mass of the sample of metal is approximately 333 grams.

8 0

2 years ago