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VikaD [51]
3 years ago
14

What is 0.00000005 in scientific notation, rounded to two significant figures?

Chemistry
1 answer:
KIM [24]3 years ago
7 0

Answer:

5×-10^8

That is the the scintific notation for 0.00000005

Answer=5×-10^8

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Calculate the oxidation number of the iodine (I) in each compound: HIO4 = I2 = NaI = HIO3 =
Makovka662 [10]
1) in periodic acid (HIO₄), iodine has oxidation number +7, hydrogen has oxidation number +1, oxygen has -2, compound has neutral charge:
+1 + x + 4 · (-2) = 0.
x = +7.

2) in molecule of iodine (I₂), iodine has oxidation number 0, because iodine is nonpolar molecule.

3) in sodium iodide (NaI), iodine has oxidation number -1, sodium has oxidation number +1:
+1 + x = 0.
x = -1.

4) in iodic acid (HIO₃), iodine has oxidation number +5, hydrogen has oxidation number +1, oxygen has -2, compound has neutral charge:
+1 + x + 3 · (-2) = 0.
x = +5.
8 0
4 years ago
Read 2 more answers
SiCl4 + H2O = H4SiO4 + HCl
vichka [17]

Hey there!

Balance the equation:

SiCl₄ + H₂O → H₄SiO₄ + HCl

Balance H.

2 on the left, 5 on the right. Add a coefficient of 3 in front of H₂O and a coefficient of 2 in front of HCl.

SiCl₄ + 3H₂O → H₄SiO₄ + 2HCl  

Balance O.

3 on the left, 4 on the right. Change the coefficient of 3 in front of H₂O to a 4.

SiCl₄ + 4H₂O → H₄SiO₄ + 2HCl  

This unbalanced our H, so change the coefficient of 2 in front of HCl to a 4.

SiCl₄ + 4H₂O → H₄SiO₄ + 4HCl  

Balance Cl.

4 on the left, 4 on the right. Already balanced.

Balance Si.

1 on the left, 1 on the right. Already balanced.

Our final balanced equation:

SiCl₄ + 4H₂O → H₄SiO₄ + 4HCl

Hope this helps!

8 0
3 years ago
An object has a mass of 18 grams and its volume is 2cm3 Calculate density:​
Natalka [10]

Answer:

9g/cm^3 is the density

Explanation:

P = m/V

P = 18/2 = 9g/cm^3

(This is more of a physics question than chem btw)

6 0
2 years ago
Read 2 more answers
Could someone please care to explain what the answer is
polet [3.4K]

Calculate the percentage composition of Ca(MnO4)2.

<u>Firstly, we see how many atoms are there for each element in the formula</u>.

Ca= 1 atom

Mn= 2 atoms

O= 8 atoms

<u>Next, we are going to consult our periodic table for the atomic mass of each element.</u>

Ca= 40

Mn= 55

O= 16

Then, we have to find the molar mass for the compound..

Here is the formula for calculating molar mass of an element:

Molar Mass= ( no. of atoms of the element × atomic mass of the element)

Now, we have to calculate the atomic mass of the compound. So using the molar mass formula for an element, we calculate the molar mass for each element then we sum up their molar masses to get the compounds molar mass.

Molar mass (Ca)= 1× 40

(Ca)= 40

Molar mass (Mn)=2×55

(Mn)= 110

Molar mass (O)= 8×16

(O)= 128

Now: Molar mass( compound)= (Ca)+(Mn)+(O)

= 40+ 110 128

= 278

This is everything we need to calculate our percentage composition for each element..

* The example says to find the percentage composition for Ca. So we only find for Ca, Which is already done using the formula and the answer is 14.39%.

To prove that your answer is correct, find the percentage composition for Mn and O as well. Then you add up their percentage compositions.

If you do and you get 100 as your answer, then your percentage compositions are correct.

Why don't you try finding the percentage composition for Mn and O, then add up all the three percentage compositions. If you 100 as their sum, then your percentage composition for each of the elements are correct.

6 0
3 years ago
How would you test to find out if<br> indigestion tablets are better than using<br> baking powder?
Orlov [11]
Go here and see how:
http://www.rsc.org/learn-chemistry/resource/res00000698/using-indigestion-tablets-to-neutralise-an-acid?cmpid=CMP00005978
7 0
4 years ago
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