Question

A resistor is connected to a 3.0 ???? battery. the power dissipated in the resistor is 4.0 ????. a second, identical resistor is connected in series with the first. how much power is dissipated in one of the resistors now?

Answer 1

Power dissipated across any resistance is given by

$P = i^2 R$

now it is given that when one resistance of value 3 ohm connected the power dissipated is 4 Watt

now another identical resistance of same value is connected then the current will reduce to half of its initial value.

now power across any one resistance is given by

$P = (\frac{i}{2})^2 R$

So now we will have

$P = \frac{i^2}{4}*R$

So now the power will become 1/4 times of initial power

So now the power will be

$P = 1 Watt$