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drek231 [11]
3 years ago
14

Objects X and Y are in a strong magnetic field. Both objects are removed from the magnetic field, after which the magnetic domai

ns in Object X remain unchanged while the domains in Object Y go from being aligned to becoming random. Which choice correctly describes Objects X and Y?
Object X is a temporary magnet because it retains the alignment of the domains, while object Y is a permanent magnet because the domains become random.

Object X is a permanent magnet because it retains the alignment of the domains, while object Y is a temporary magnet because the domains became random.

Object X is a temporary magnet because it retains the alignment of the domains, while object Y is not magnetic at all because its domains are not aligned.

Object X is a permanent magnet because it retains the alignment of the domains, while object Y is not magnetic at all because its domains are not aligned.
Physics
1 answer:
Nana76 [90]3 years ago
5 0
<span>Objects X and Y are in a strong magnetic field.
Both objects are removed from the magnetic field, after which
the magnetic domains in Object X remain unchanged while the
domains in Object Y go from being aligned to becoming random.

Object X is a permanent magnet because it retains the alignment
of the domains, while object Y is a temporary magnet because the
domains became random.  (B)</span>
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Two large rectangular aluminum plates of area 180 cm2 face each other with a separation of 3 mm between them. The plates are cha
lbvjy [14]

Answer:

Electric flux;

Φ = 30.095 × 10⁴ N.m²/C

Explanation:

We are given;

Charge on plate; q = 17 µC = 17 × 10^(-6) C

Area of the plates; A_p = 180 cm² = 180 × 10^(-4) m²

Angle between the normal of the area and electric field; θ = 4°

Radius;r = 3 cm = 3 × 10^(-2) m = 0.03 m

Permittivity of free space;ε_o = 8.85 × 10^(-12) C²/N.m²

The charge density on the plate is given by the formula;

σ = q/A_p

Thus;

σ = (17 × 10^(-6))/(180 × 10^(-4))

σ = 0.944 × 10^(-3) C/m²

Also, the electric field is given by the formula;

E = σ/ε_o

E = (0.944 × 10^(-3))/(8.85 × 10^(-12))

E = 1.067 × 10^(8) N/C

Now, the formula for electric flux for uniform electric field is given as;

Φ = EAcos θ

Where A = πr² = π × 0.03² = 9π × 10^(-4) m²

Thus;

Φ = 1.067 × 10^(8) × 9π × 10^(-4) × cos 4

Φ = 30.095 × 10⁴ N.m²/C

3 0
3 years ago
1. Why should you use scientific notation when writing big numbers?
Fynjy0 [20]

Answer:

It helps the answer look clean. It also makes the work easier to work with.

Explanation:

Instead of writing a lot of zeros, all you have to do is add exponents to the number to show how much the decimal moved.

6 0
3 years ago
Paki po plss po plssssss​
slega [8]

Answer:A language is a structured system of communication. Language, in a broader sense, is the method of communication that involves the use of – particularly human – languages. The scientific study of language is called linguistics

Explanation:

7 0
3 years ago
A 328-kg car moving at 19.1 m/s in the x direction hits from behind a second car moving at 13.0 m/s in the same direction. If th
Jet001 [13]

Answer:

14.04 m/s

Explanation:

To find the velocity of the first car after the collision, we can use the equation of conservation of momentum:

m1v1 + m2v2 = m1'v1' + m2'v2'

We have the following data:

m1 = m1' = 328,

m2 = m2' = 790,

v1 = 19.1,

v2 = 13,

v2' = 15.1.

Using this data, we can find v1' (final velocity of the first car):

328 * 19.1 + 790 * 13 = 328 * v1' + 790 * 15.1

16534.8 = 328 * v1' + 11929

328 * v1' = 4605.8

v1' = 14.04 m/s

3 0
3 years ago
A force AB of length 100m and weight 600N has its centre of gravity 4.0 m from the end, and lies on horizontal ground calculate
Stells [14]

Answer:

F = 24 N

Explanation:

In this exercise we have a bar l = 100 m with a center of gravity x = 4 m, which force is needed to lift it from the other end

Let's use the rotational equilibrium relationship, where we consider the counterclockwise rotations as positive and fix the reference system at the point closest to the center of gravity

           ∑ τ = 0

           F l -x W = 0

           F = \frac{x}{l} \  W

let's calculate

          F = \frac{4}{100}4/100 600

          F = 24 N

8 0
3 years ago
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