Answer:
Bottom of mirror to ground = 0.88m
Top of mirror to ground = 1.835m
Explanation:
From the image attached;
- A D is the distance between his eyes and the ground which is 1.76m
- A F is the distance between his eyes and the top of his head which is 0.15
-G D is the distance from the top of the mirror to the ground
-B D is distance from the bottom of mirror to the ground
From law of refraction, θi = θr and from trigonometric ratios, we can say that;
A B/B C = B D/B C
Thus, BC will cancel out and we have;
A B = B D
Now, from the diagram,
A D = A B + B D
Thus, since A B = B D
A D = B D + B D = 2B D
From the question, A D = 1.76,Thus
B D = A D/2 = 1.76/2 = 0.88m
Now,for the top of the mirror;
G D = G B + B D
As said before From law of refraction, θi = θr and from trigonometric ratios, we can say that;
G A/G E = G F/G E
G E will cancel out and we have;
G A = G F
Now, from the diagram, A F = G F + G A
Now we already know A F = 0.15m and since G A = G F,
Thus, 0.15 = G A + G A = 2G A
G A = 0.15/2 = 0.075m
From the diagram, G A + A D will give us the height of the top of the mirror above the ground.
Thus,
G D = G A + A D = 0.075 + 1.76 = 1.835m