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Aliun [14]
3 years ago
11

3.5 g of a hydrocarbon fuel is burned in a vessel that contains 250. grams of water initially at 25.00 C. After the combustion,

the temperature of the water is 26.55 C. How much heat is evolved per gram of fuel burned?
1. 73.5 J/g
2. 1263 J/g
3. 463 J/g
4. 143 J/g
5. 1105 J/g
6. 1764 J/g
7. 26555 J/g
8. 511 J/g
Physics
1 answer:
kherson [118]3 years ago
6 0

Answer:

3.) 463 J/g

Explanation:

Heat given by the fuel is used to increase the temperature of the water

so it is given as

Q = ms\Delta T

here we will have

m = 250 g

\Delta T = 26.55 - 25

now we also know that

s = 4186

so we have

Q = (0.250)(4186)(26.55 - 25)

Q = 1622.075 J

so 3.5 g fuel gives above energy

so per gram of fuel will have total energy given as

Q = \frac{1622.075}{3.5}

Q = 463.45 J/g

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Answer:

It transformed into ash particles and a slight gaseous state

Explanation:

5 0
3 years ago
A hard-boiled egg of mass 46.0 gg moves on the end of a spring with force constant 25.6 N/mN/m . The egg is released from rest a
soldi70 [24.7K]

Answer:

0.022kg/s

Explanation:

We are given that

Mass of boiled egg=46 g=\frac{46}{1000} kg=0.046 kg

1kg=1000 g

Constant force=F=25.6 N/m

Initial displacement=A_1=0.296 m

Final displacement=A_2=0.12 m

Time=t=4.55 s

Damping force=F_x=-bv_x

We have to find the  magnitude of damping constant b.

We know that the displacement of the oscillator under damping motion is given by

x=Ae^{-\frac{b}{2m}t}cos(w't+\phi)

For maximum displacement cos(w't+\phi)=1

Therefore , x=A_2

Substitute the values

A_2=A_1e^{-\frac{-b}{2m}t}

e^{-\frac{b}{2m}t}=\frac{A_2}{A_1}

-\frac{b}{2m}t=ln\frac{A_2}{A_1}

lnx=y\implies x=e^y

Substitute the values

-\frac{b}{2\times 0.046}\times 4.55=ln\frac{0.12}{0.296}

\frac{2\times 0.046}{4.55b}=ln\frac{0.296}{0.12}

\frac{2\times 0.046}{4.55}=0.9b

b=\frac{2\times 0.46}{4.55\times 0.9}=0.022kg/s

Hence,the  magnitude of damping constant b=0.022kg/s

3 0
3 years ago
How do I solve such problem???
labwork [276]

1).  Calculate how long it takes an object to fall 4,000 m after it's dropped. (Use D = (1/2) (g) (T²) .  D is 4,000 m.  g = 9.8 m/s².  Find T .)

2).  Calculate how far the object will move HORIZONTALLY in that length of time, if it's moving at 75 m/s.  (Distance = (75 m/s) x (time) . )

6 0
3 years ago
while hunting in a cave a bat emits sounds wave of frequency 39 kilo hartz were moving towards a wall with a constant velocity o
MariettaO [177]

Complete question:

while hunting in a cave a bat emits sounds wave of frequency 39 kilo hartz were moving towards a wall with a constant velocity of 8.32 meters per second take the speed of sound as 340 meters per second. calculate the frequency​ reflected off the wall to the bat?

Answer:

The frequency reflected by the stationary wall to the bat is 41 kHz

Explanation:

Given;

frequency emitted by the bat, = 39 kHz

velocity of the bat, v_b = 8.32 m/s

speed of sound in air, v = 340 m/s

The apparent frequency of sound striking the wall is calculated as;

f' = f(\frac{v}{v- v_b} )\\\\f' = 39,000(\frac{340}{340 -8.32} )\\\\f' = 39978.29 \ Hz

The frequency reflected by the stationary wall to the bat is calculated as;

f_s = f'(\frac{v + v_b}{v} )\\\\f_s = 39978.29(\frac{340 + 8.32}{340} )\\\\f_s = 40,956.56 \ Hz

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3 0
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geniusboy [140]

Answer:

p = 4000 kg-m/s

Explanation:

Given that,

The mass of a truck, m = 200 kg

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We need to find the momentum of the truck. The formula for momentum is given by :

p = mv

so,

p=200\times 20\\\\p=4000\ kg-m/s

So, the momentum of the truck is equal to 4000 kg-m/s.

8 0
3 years ago
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