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Paraphin [41]
3 years ago
7

The density of a test tube is 2.3g/cm3. The volume of the test tube is 4 cm3. What is

Chemistry
1 answer:
Lesechka [4]3 years ago
4 0

Answer:

B. 9.2g

Explanation:

Density is mass over volume:

d=m/v

Let's plug in the values:

2.3=m/4

Now we solve like an equation:

2.3*4=(m/4)*4

9.2=m

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How does the emission spectrum support the idea of quantized energy levels
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Explanation:

Different atoms absorb and emit specific wavelengths of electromagnetic radiation and nothing in between. These absorption and emission spectra are actually used to identify atoms of elements in a substance. This phenomenon is explained by Bohr's theory of quantized energy levels in an atom – called orbital levels. When an electron 'jumps' from a lower to higher orbital level, it absorbs a specific wavelength of electromagnetic radiation specific to the ‘jump’. Vice versa, when an electron 'jumps' to a lower orbital level is emits an equivalent  and specific wavelength of electromagnetic radiation.  

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4 years ago
The compound consists of 40.1% carbon, 6.6% hydrogen and 53.3% oxygen. Its relative density with respect to hydrogen is -15. Wha
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https://socratic.org/answers/220339

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3 years ago
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3 years ago
Calculate the electrical energy per gram of anode material for the following reaction at 298 K:
solmaris [256]

43.8 kJ

<h3>Explanation</h3>

There are two electrodes in a voltaic cell. Which one is the anode?

The lithium atom used to have no oxygen atoms when it was on the reactant side. It gains two oxygen atoms after the reaction. It has gained more oxygen atoms than the manganese atom. Gaining oxygen is oxidation. As a result, lithium is being oxidized.

Oxidation takes place at the anode of a cell. Therefore, the anode of this cell is made of lithium.

Lithium has an atomic mass of 6.94. Each gram of Li would contain 1/6.94 = 0.144 moles of Li atoms. Each Li atom loses one electron in this cell. Therefore, the number of electron transferred, <em>n</em>, equals 0.144 moles for each gram of the anode.

Let w_\text{max} represents the electrical energy produced.

w_\text{max} = n \cdot F \cdot E_\text{cell}, where

  • <em>n</em> is the <em>number of moles</em> electrons transferred,
  • <em>F</em> is the Faraday's constant,
  • <em>E</em>_\text{cell} is the cell potential,

<em>n </em>= 0.144 mol, as shown above, and

<em>F </em>= 96.486 kJ / (\text{V} \cdot \text{mol} \; \text{e}^{-}).

Therefore,

w_\text{max} = n \cdot F \cdot E\\\phantom{w_\text{max}} = 0.144 \times 96.486 \times 3.15 \\\phantom{w_\text{max}} = 43.8 \; \text{kJ}.

3 0
3 years ago
WILL MARK BRAINLIEST
den301095 [7]
The answer is C. Life
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