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harkovskaia [24]
3 years ago
5

PLEASE HURRY!!! 25 POINTS!! how do geologic processes help explain the limited spread of monotremes

Chemistry
1 answer:
zaharov [31]3 years ago
5 0
Relating to the study of the earth's physical structure and substance.
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What type of element is most abundant: metals, nonmetals, or metalloids?
AnnyKZ [126]
Metals are the most abundant
7 0
3 years ago
Read 2 more answers
The concentration of pb2+ in a solution saturated with pbbr2(s) is 2.14 ✕ 10-2 m. calculate ksp for pbbr2.
Ugo [173]
Concentration = 2.14 âś• 10-2 m 
For [Br-], there are 2 ions so 2 x 2.14 x 10^-2 =4.28 x 10^-2  
Ksp = [Pb][Br]^2 = 2.14 âś• 10-2 x (4.28 x 10^-2 )^2 = 39.20 x 10^-6 
Ksp = 3.92 x 10^-5
3 0
3 years ago
Read 2 more answers
Consider the following chemical reaction in a small volume of solution. According to LeChatelier’s Principle, which perturbation
stiks02 [169]

Answer:

Decreasing the temperature will shift the equilibrium leftwards towards reactants.

Explanation:

Hello!

In this case, since the reaction between chromate anions and hydrogen ions yields dichromate anions, water and heat, we can infer this is an exothermic reaction by which heat is released (remember in endothermic reactions heat is absorbed as a reactant), it means that considering the LeChatelier’s which states that increasing the temperature of an exothermic reaction shifts the equilibrium leftwards since heat is a product, otherwise (decreasing the temperature) the equilibrium will be shifted rightwards.

Therefore, decreasing the temperature is the perturbation that will shift the equilibrium leftwards towards the reactants.

Best regards!

7 0
2 years ago
The air inside a hot-air balloon is heated to 59.00 °C (Tinitial) and then cools to 39.00 °C (Tfinal). By what percentage does t
Mama L [17]

Answer:

6.1%

Explanation:

Assuming pressure inside balloon remains constant during the temperature change.

Therefore, as per Charles' law  at constant pressure,

\frac{V_1}{T_1} =\frac{V_2}{T_2}

T_2=39\°\ C=39+273=312\ K

T_1=59°\ C=273+59=332\ K

V_2=V_1\times \frac{T_2}{T_1} \\=V_1\times\frac{312}{332}\\=0.939V_1

Percentage change in volume

\%\ change\ in\ volume=\frac{V_1-0.939V_1}{V_1} \times 100\\=6.1\%

Change in volume of the balloon is 6.1%

4 0
3 years ago
Calculate the vapor pressure at 25 ?c of hexane above the solution. the vapor pressure of pure hexane at 25 ?c is 151 torr.
Studentka2010 [4]
One of the many ways in order to solve for the vapor pressure of pure components at a given temperature is through the Antoine's equation which is written below,
                                    P = 10^(A - B/C+T)
where A, B, and C are constants and T is the temperature in °C and P is the vapor pressure in mm Hg. 
For hexane,
                             A = 7.01
                             B = 1246.33
                             C = 232.988

Substituting the known values,
                            P = 10^(7.01 - 1246.33/232.988+25)
                             <em> P = 151.199 mm Hg</em>
8 0
3 years ago
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