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3 years ago

Of the metals pb, mg, au, and na, which will not spontaneously donate electrons to copper in solution?

2 answers:

7 0

Au :)

Pb + Cu(2+)---> Pb(2+) + Cu
Mg + Cu(2+)---> Mg(2+) + Cu
2Na + Cu(2+) ---> 2Na(+) + Cu

Au + Cu(2+) ---> (this reaction is not possible)

QveST [7]3 years ago

3 0

Answer:

Au will not spontaneously donate electrons to copper in solution.

Explanation:

Based on the activity series of metals:

K > Na > Ca> Mg> Al> Zn>Fe> Sn > Pb> H> Cu> Hg> Ag> Au

Among the given metals Pb, Mg, Au and Na, the most reactive metals is Na, followed by Mg, Pb and Au. All three metals Pb, Mg, and Na are above Cu in the activity series. So these metals will spontaneously donate electrons to Cu in solution. Au being lower than Cu in the activity will not spontaneously donate electrons to copper in solution.

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Consider 2 Al + 6 HCl → 2 AlCl3 + 3 H2 , the reaction of Al with HCl to produce hydrogen gas. What is the pressure of H2 if the

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Answer : The pressure of hydrogen gas is 8.96 atm.

Explanation :

The given balanced chemical reaction is:

$2Al+6HCl\rightarrow 2AlCl_3+3H_2$

From the balanced chemical reaction we conclude that,

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So, 4.50 moles of Al react to give $\frac{3}{2}\times 4.50=6.75$ moles of $H_2$ gas

Now we have to calculate the moles of $H_2$ gas when percent yield is 75.4.

$\text{The moles of }H_2=75.4\% \times 6.75=\frac{75.4}{100}\times 6.75=5.09moles$

Now we have to calculate the pressure of $H_2$ gas.

Using ideal gas equation :

PV = nRT

where,

P = Pressure of hydrogen gas = ?

V = Volume of the hydrogen gas = 14.0 L

n = number of moles of hydrogen gas = 5.09 moles

R = Gas constant = $0.0821L.atm/mol.K$

T = Temperature of hydrogen gas = 300 K

Putting values in above equation, we get:

$P\times 14.0L=5.09mol\times 0.0821L.atm/mol.K\times 300K\\\\P=8.96atm$

Therefore, the pressure of hydrogen gas is 8.96 atm.

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