All categories

3 years ago

Are forces present even when there is no movement?

Physics

1 answer:

My name is Ann [436]3 years ago

4 0

Answer:

Yes, gravitational force is everywhere. Even if you don't move or move, or wherever you are, there is gravitational force.

You might be interested in

Pls answer it plssss

Sonbull [250]

Answer:

1.Stronger bones 2.Joint flexibility

3 0

3 years ago

Definition of continental polar

kipiarov [429]

Answer:

Continental polar (cP) or continental arctic (cA) air masses are cold, dry, and stable. These air masses originate over northern Canada and Alaska as a result of radiational cooling. Maritime polar (mP) air masses are cool, moist, and unstable.

Explanation:

8 0

3 years ago

Read 2 more answers

To study the properties of various particles, you can accelerate the particles with electric fields. A positron is a particle wi

Gnom [1K]

Answer:

(a) Acceleration of positron is 6.03 x 10¹³ m/s²

(b) Speed of positron after 8.70 x 10⁻⁹ s is 5.24 x 10⁵ m/s

Explanation:

Given :

Constant electric field, E = 343 N/C

Mass of positron, m = 9.1 x 10⁻³¹ kg

Charge of positron, q = +e = 1.6 x 10⁻¹⁹ C

(a) Coulomb force on the positron is determine by the relation :

F = q x E ....(1)

But, force is also equals to product of mass and acceleration. So,

F = ma .....(2)

Here a is acceleration.

From equation (1) and (2).

m x a = q x E

$a=\frac{qE}{m}$

Substitute the values of q, E and m in the above equation.

$a=\frac{1.6\times10^{-19}\times 343}{9.1\times10^{-31} }$

a = 6.03 x 10¹³ m/s²

(b) Initially, the positron is at rest, so its initial speed is zero.

The equation of motion for positron is :

v = u + at

Here v is final speed, u is initial speed and t is time.

Since, u is zero, so the equation becomes :

v = at

Substitute 8.70 x 10⁻⁹ s for t and 6.03 x 10¹³ m/s² for a in the above equation.

v = 6.03 x 10¹³ x 8.70 x 10⁻⁹ m/s

v = 5.24 x 10⁵ m/s

6 0

3 years ago

Question is down below need rply fast

My name is Ann [436]

The X and Y components are as follows;

1. X = 35 * cos 57 = 19. 1m/s; Y = 35 * sin 57 = 29.4 m/s

2. X = 12 * -cos 34 = -10 m/s; Y = 12 * -sin 34 = -6.7 m/s

3. X = 8 * -cos 90 = 0 m/s; Y = 12 -sin 90 = -8 m/s

4. X = 20 * cos 75 = 5. 2m/s; Y = 20 * (-sin 75) = -19.3 m/s

<h3>What are the horizontal and vertical components of the vectors?</h3>

The horizontal and vertical components of the velocities are given as follows:

Horizontal component, X = x cos θ
Vertical component, Y = y sin θ

1. 35 m/s at 57° from x-axis

X = 35 * cos 57 = 19. 1m/s

Y = 35 * sin 57 = 29.4 m/s

2. 12m/s at 34° S of W

X = 12 * -cos 34 = -10 m/s

Y = 12 * -sin 34 = -6.7 m/s

3. 8 m/s at South

X = 8 * -cos 90 = 0 m/s

Y = 12 -sin 90 = -8 m/s

4. 20 m/s at 275° from x-axis

X = 20 * cos 75 = 5. 2m/s

Y = 20 * (-sin 75) = -19.3 m/s

In conclusion, the X and Y components are found by taking cosines and sine of the angles.

Learn more about horizontal and vertical components at: brainly.com/question/26446720

#SPJ1

8 0

2 years ago

Considerable scientific work is currently under way to determine whether weak oscillating magnetic fields such as those found ne

VLD [36.1K]

Answer:

The the maximum emf is $2.52\times10^{-11}\ V$

Explanation:

Given that,

Magnetic field $B = 1.40\times10^{-3}\ T$

Frequency = 60 Hz

Diameter = 7.8 μm

We need to calculate the maximum emf

Using formula of emf

$\epsilon=NBA\omega$

Where, N = number of turns

B= magnetic field

A = area

Put the value in to the formula

$\epsilon=1\times1.40\times10^{-3}\times\pi\times(\dfrac{7.8\times10^{-6}}{2})^2\times2\times\pi\times60$

$\epsilon=2.52\times10^{-11}\ V$

Hence, The the maximum emf is $2.52\times10^{-11}\ V$

5 0

3 years ago