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Reptile [31]
3 years ago
5

Can someone please help me

Chemistry
2 answers:
Bumek [7]3 years ago
5 0
The answer is A. I think
AVprozaik [17]3 years ago
5 0
The awnser is 4. Structure D.Hope it helped!
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If you have 16 g of manganese (II) nitrate tetrahydrate, how much water is required to prepare 0.16 M solution from this amount
nirvana33 [79]

<u>Answer:</u> The volume of water required is 398 mL

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

We are given:

Mass of solute (manganese (II) nitrate tetrahydrate) = 16 g

Molar mass of manganese (II) nitrate tetrahydrate = 251 g/mol

Molarity of solution = 0.16 M

Putting values in above equation, we get:

0.16M=\frac{16g\times 1000}{251g/mol\times \text{Volume of solution}}\\\\\text{Volume of solution}=398mL

Hence, the volume of water required is 398 mL

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3 years ago
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Vesnalui [34]

Answer:

D

Explanation:

It is higher in the air, so it will fall faster then the other apples.

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GarryVolchara [31]

Ionization energy generally decreases down a group because as one moves down a group, the outermost electron moves <u>further away </u>from the nucleus and it takes <u>less</u> energy to remove it.

Ionization energy, also known as ionization energy, would be the minimal amount of energy needed to free an isolated gaseous atom's or molecule's least loosely bonded electron.

First ionization energy often drops as you advance down a group on the periodic table. This occurs even though the outermost electron would be typically held less securely and can be removed with less energy since it travels farther away from the nucleus.

Therefore, Ionization energy generally decreases down a group because as one moves down a group, the outermost electron moves <u>further away </u>from the nucleus and it takes <u>less</u> energy to remove it.

To know more about Ionization energy

brainly.com/question/16243729

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C3H8 + 5 O2 --&gt; 3 CO2 + 4 H2O
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