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zubka84 [21]
3 years ago
15

Chemical weathering occurs faster in warm, tropical climates, although it happens in cold climates as well. Describe some condit

ions in Antarctica that could lead to chemical weathering.
Chemistry
2 answers:
vredina [299]3 years ago
7 0

Answer:

Oxidation, acidification and hydrolisis.

Explanation:

Hello,

It is widely known that chemical weathering occurs when rocks undergo chemical reactions to yield different minerals. Water, acids, and oxygen are  chemical weathering promoters causing dramatic results over the time.

In the Antarctica, the following conditions would produce chemical weathering:

- Oxidation: is understood by formation of oxides when the rocks react with the environmental gaseous oxygen or the inner oxygen in water.

- Acidification: when oxides such as CO₂, NOₓ or SOₓ react with the water in the atmosphere, their corresponding acids are produced so when it rains they fall over the rocks creating sink holes and caves.

- Hydrolysis: it is caused when water dissolves minerals in a rock, producing different mineral compounds. For instance, feldspar crystals inside the granite react by hydrolysis, forming clay minerals which weakens the rock, making it more likely to break.

Best regards.

andrew11 [14]3 years ago
6 0

Oxidation, Dissolving in acid, Hydrolysis ,Water absorption and Hydration

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A bicyclist travels the first 800 m of a trip with a speed of 10 m/s, the next 500 m with an
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Answer:9.18 m/s

Explanation:

The average speed for the entire trip is found ......total distance/total time. Remember r*t=d, so divide both sides by t and get r = d/t.

So the cyclist went 800+500+1200 m = 2500 m for total distance.

10t =800 leads to t=80 sec

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In the gas-phase reaction 2 A + B ⇌ 3 C + 2 D, it was found that, when 1.00 mol A, 2.00 mol B, and 1.00 mol D were mixed and all
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Answer:

(i)The mole fractions are :

  • A=\frac{0.4}{4.3} \\=0.0930
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  • C=\frac{0.9}{4.3} \\=0.2093
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(ii)K=0.4508

(iii)ΔG = 1.974kJ

Explanation:

The given equation is :

2A+B⇄3C+2D

Let \alpha be the number of moles dissociated per mole of B

Thus ,

<em>The initial number of moles of :</em>

  • A=1
  • B=2
  • C=0
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2A\\(1-2\alpha)     +  B\\2(1-\alpha)  ⇄  3C\\(3\alpha)   + 2D\\(1+2\alpha)

And finally the number of moles of C[tex] is 0.9Thus ,[tex]3\alpha=0.9\\\alpha=0.3[tex]The final number of moles of:[tex]A = 1-2\alpha=1-2*0.3=0.4mol[tex] [tex]B=2(1-\alpha)=2(1-0.3)=1.4mol[tex][tex]D=1+2\alpha=1+2*0.3=1.6mol[tex]Thus , total number of moles are : 0.4+1.4+0.9+1.6=4.3(i)The mole fractions are : [tex]A=\frac{0.4}{4.3} \\=0.0930

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(ii)

K=\frac{(P_C^3)(P_D^2)}{(P_A^2)(P_B)}

Where ,

P_A,P_B,P_C,P_D are the partial pressures of A,B,C,D respectively.

Total pressure = 1 bar .

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<em>P_B= 0.3256*1=0.3256</em>

<em>P_C= 0.2093*1=0.2093</em>

<em>P_D= 0.3721*1=0.3721</em>

K=\frac{0.2093^3*0.3721^2}{0.0930^2*0.3256} \\K=0.4508

(iii)

ΔG=-RTlnK\\

ΔG = -8.314*(273+25)*ln(0.4508)\\=1973.96J\\=1.974kJ

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