The distance between two basket ball sized aluminium balls is 9714 m.
Explanation:
Coulomb's law, or Coulomb's inverse-square law, is an experimental law of physics that quantifies the amount of force between two stationary, electrically charged particles. The electric force between charged bodies at rest is conventionally called electrostatic force or Coulomb force .
Coulomb's law formula => F = (k * Qb1 * Qb2)/r²
Given data :-
charge on ball 1 Qb1 = 6C
charge on ball 2 Qb2 = 14C
Force exerted F = 8000 N
k = 8.988 x 10^9 Nm²C−²(coulomb's constant).
substituting given values in the coulomb's formula
8000 = (( 8.988 x 10^9)*6*14)/r²
shifting r and 8000 to other sides
r² = (756 * 10^9)/8000
r = 9714 m.
Therefore the distance between two balls is r = 9714 m.
<span>internet tension = mass * acceleration internet tension = 23 – Friction tension = 14 * acceleration Friction tension = µ * 14 * 9.8 = µ * 137.2 23 – µ * 137.2 = 14 * acceleration Distance = undemanding speed * time undemanding speed = ½ * (preliminary speed + very final speed) Distance = ½ * (preliminary speed + very final speed) * time Distance = 8.a million m, preliminary speed = 0 m/s, very final speed = a million.8 m/s 8.a million = ½ * (0 + a million.8) * t Time = 8.a million ÷ 0.9 = 9 seconds Acceleration = (very final speed – preliminary speed) ÷ time Acceleration = (a million.8 – 0) ÷ 9 = 0.2 m/s^2 23 – µ * 137.2 = 14 * 0.2 resolve for µ</span>
Based on the length of the Ethernet cable and the mass, the tension in the cable can be found to be 80 N.
<h3>How much tension is in the cable?</h3>
The tension in the cable can be found as:
= 4 x mass x length x frequency
Solving for the frequency is:
= 1 / (0.800 / 4)
= 1 / 0.20
= 5.0 Hz
The tension is therefore:
= 4 x 0.20 x 4.00 x 5
= 80N
Find out more on tension at brainly.com/question/14336853
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