A chair of weight 90.0 N lies atop a horizontal floor; the floor is not frictionless. You push on the chair with a force of F =
38.0 N directed at an angle of 42.0 degrees below the horizontal and the chair slides along the floor.
Using newton's laws, calculate n, the magnitude of the normal force that the floor exerts on the chair.
Using newton's laws, calculate n, the magnitude of the normal force that the floor exerts on the chair.
1 answer:
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Answer:
A.
B. t = 50 s
Explanation:
A. The vectorial equation of the person who is getting closer to the other person is:
r: position vector
v: speed vector = 6m/s i (if you consider the motion as a horizontal motion)
Then, you replace and obtain:
B. The time is:
d: distance to the observer = 300m
v: speed of the person on the car = 6.00 m/s
Answer:
The final velocity of the thrower is and the final velocity of the catcher is
.
Explanation:
Given:
The mass of the thrower, .
The mass of the catcher, .
The mass of the ball, .
Initial velocity of the thrower,
Final velocity of the ball,
Initial velocity of the catcher,
Consider that the final velocity of the thrower is . From the conservation of momentum,
Consider that the final velocity of the catcher is . From the conservation of momentum,
Thus, the final velocity of thrower is and that for the catcher is
.
Answer:
0.75 m
Explanation:
Let's call the distance between the bulb and the mirror x.
The bulb and the length of the mirror form a triangle. The mirror and the illuminated area on the floor form a trapezoid. If we extend the lines from the mirror edge to the reflected image of the bulb, we turn that trapezoid into a large triangle. This triangle and the small triangle are similar. So we can say:
x / 0.4 = (3 + x) / 2
Solving for x:
2x = 0.4 (3 + x)
2x = 1.2 + 0.4 x
1.6 x = 1.2
x = 0.75
So the bulb should located no more than 0.75 m from the mirror.
